All categories

3 years ago

What is the average rate of change in f(x) over the interval [4,13]?

Mathematics

2 answers:

mestny [16]3 years ago

8 0

we know that

Average Rate of Change. is the change in the y-value divided by the change in the x-value for two distinct points on the graph

$A=\frac{(f(b)-f(a))}{(b-a)}$

in this problem

$a=4\\ b=13\\ f(a)=f(4)=8\\ f(b)=f(13)=11$

substitute the values in the formula above

$A=\frac{(11-8)}{(13-4)} \\ \\ A=\frac{3}{9}$

Divide by $3$ both numerator and denominator

$A=\frac{1}{3}$

therefore

the answer is

$\frac{1}{3}$

faltersainse [42]3 years ago

6 0

The awnser is a)1/3
hope this will help

You might be interested in

Hello please help me answer :) ( WILL GIVE BRAINLST)

Vanyuwa [196]

Answer:

Answer is given

:) mark me brainliest

4 0

3 years ago

A regulation football field is 300 feet by 160

igomit [66]

Answer:

366.7424164 feet

Step-by-step explanation:

330x160

Use pythag theorem

a²+b²=c²

330²+160²=c²

c=366.7424164 feet

5 0

3 years ago

The amount of time, in minutes, that a woman must wait for a cab is uniformly distributed between zero and 12 minutes, inclusive

murzikaleks [220]

Answer:

$P(X\leq x) =\frac{x-a}{b-a}, a \leq x \leq b$

And using this formula we have this:

$P(X$

Then we can conclude that the probability that that a person waits fewer than 11 minutes is approximately 0.917

Step-by-step explanation:

Let X the random variable of interest that a woman must wait for a cab"the amount of time in minutes " and we know that the distribution for this random variable is given by:

$X \sim Unif (a=0, b =12)$

And we want to find the following probability:

$P(X$

And for this case we can use the cumulative distribution function given by:

$P(X\leq x) =\frac{x-a}{b-a}, a \leq x \leq b$

And using this formula we have this:

$P(X$

Then we can conclude that the probability that that a person waits fewer than 11 minutes is approximately 0.917

7 0

3 years ago

Help me please,Thanks

ehidna [41]

The answer is 1/16 i think. Hope this helps! :)

3 0

3 years ago

Read 2 more answers

A courier service company wishes to estimate the proportion of people in various states that will use its services. Suppose the

a_sh-v [17]

Answer:

Probability that the sample proportion will be less than 0.03 is 0.10204.

Step-by-step explanation:

We are given that a courier service company wishes to estimate the proportion of people in various states that will use its services. Suppose the true proportion is 0.04.

Also, 469 are sampled.

Let $\hat p$ = sample proportion

The z-score probability distribution for sample proportion is given by;

Z = $\frac{ \hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ~ N(0,1)

where, $\hat p$ = sample proportion

p = true proportion = 0.04

n = sample size = 469

The Z-score measures how many standard deviations the measure is away from the mean. After finding the Z-score, we look at the z-score table and find the p-value (area) associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X.

So, probability that the sample proportion will be less than 0.03 is given by = P( $\hat p$ < 0.03)

P( $\hat p$ < 0.03) = P( $\frac{ \hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < $\frac{0.03-0.04}{\sqrt{\frac{0.03(1-0.03)}{469} } }$ ) = P(Z < -1.27) = 1 - P(Z $\leq$ 1.27)

= 1 - 0.89796 = 0.10204

Now, in the z table the P(Z $\leq$ x) or P(Z < x) is given. So, the above probability is calculated by looking at the value of x = 1.27 in the z table which has an area of 0.89796.

Therefore, probability that the sample proportion will be less than 0.03 is 0.10204.

5 0

3 years ago