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3 years ago

Find the median, first quartile, third quartile, and interquartile range of the data.

Mathematics

1 answer:

xz_007 [3.2K]3 years ago

4 0

Median: 133.5

Lower/First quartile: 128

Upper/Third quartile: 139

Interquartile range: 139 - 128 = 11

so your interquartile range is 11

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Need help with Writeing the quadratic function with at two zero where x = ‒2 and x = 0.

Pachacha [2.7K]

We can create the equation like this:
(x +2) * (x +0)
x^2 + 2x + 0 = 0

8 0

3 years ago

2/3 - 4x + 7/2 = -9x + 5/6 apply the properties.. step by step

Nutka1998 [239]

Answer:

x=5/13

Step-by-step explanation:

2/3+7/2=9x+5/6+4x

2/3+7/2-5/6=9x+4x

lcm of 2,3,6=6

2/3=4/6 7/2=21/6 5/6=5/6

4/6+21/6-5/6=9x+4x

30/6=13x

5=13x

x=5/13

8 0

3 years ago

Read 2 more answers

A dot plot titled hours of practice this week going from 0 to 4. 0 has 1 dot, 1 has 2 dots, 2 has 0 dots, 3 has 4 dots, and 4 ha

WITCHER [35]

Answer:

1, 2, 3, 5

Step-by-step explanation:

I took the quiz

4 0

4 years ago

The average number of traffic tickets issued in a city on any given day

Anton [14]

Answer:

The most tickets were written on Saturday .On Saturday 325 tickets were issued

Step-by-step explanation:

The average number of traffic tickets issued in a city on any given day Sunday-Saturday can be approximated by

$T(x) = -6x^2 + 84x + 37$

Where x represents the number of days after Sunday

T(x) represents the number of traffic tickets issued.

Sunday = x=0

Monday = x=1

Tuesday = x=2

Wednesday = x=3

Thursday = x =4

Friday = x=5

Saturday = x=6

Substitute x= 0

$T(x) = -6x^2 + 84x + 37\\T(x) = -6(0)^2 + 84(0) + 37\\T(x)=37$

On Sunday 37 tickets were issued

Substitute x= 1

$T(x) = -6x^2 + 84x + 37\\T(x) = -6(1)^2 + 84(1) + 37\\T(x)=115$

On Monday 115 tickets were issued

Substitute x= 2

$T(x) = -6x^2 + 84x + 37\\T(x) = -6(2)^2 + 84(2) + 37\\T(x)=181$

On Tuesday 181 tickets were issued

Substitute x= 3

$T(x) = -6x^2 + 84x + 37\\T(x) = -6(3)^2 + 84(3) + 37\\T(x)=235$

On Wednesday 235 tickets were issued

Substitute x= 4

$T(x) = -6x^2 + 84x + 37\\T(x) = -6(4)^2 + 84(4) + 37\\T(x)=277$

On Thursday 277 tickets were issued

Substitute x= 5

$T(x) = -6x^2 + 84x + 37\\T(x) = -6(5)^2 + 84(5) + 37\\T(x)=307$

On Friday 307 tickets were issued

Substitute x= 6

$T(x) = -6x^2 + 84x + 37\\T(x) = -6(6)^2 + 84(6) + 37\\T(x)=325$

On Saturday 325 tickets were issued

Hence the most tickets were written on Saturday .On Saturday 325 tickets were issued

6 0

3 years ago

Solve for x: 3(x + 1) = −2(x − 1) − 4 1 −1 −5 −25

LekaFEV [45]

Answer:

x = - 1

Step-by-step explanation:

3(x + 1) = - 2(x - 1) - 4 ← distribute parenthesis on both sides

3x + 3 = - 2x + 2 - 4

3x + 3 = - 2x - 2 ( add 2x to both sides )

5x + 3 = - 2 ( subtract 3 from both sides )

5x = - 5 ( divide both sides by 5 )

x = - 1

7 0

2 years ago