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stira [4]
2 years ago
15

Find the median, first quartile, third quartile, and interquartile range of the data.

Mathematics
1 answer:
xz_007 [3.2K]2 years ago
4 0

Median: 133.5

Lower/First quartile: 128

Upper/Third quartile: 139

Interquartile range: 139 - 128 = 11

so your interquartile range is 11

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Heights​ (cm) and weights​ (kg) are measured for 100 randomly selected adult​ males, and range from heights of 138 to 190 cm and
mart [117]

Answer:

Best predicted value of y' = 86.16 kg

Step-by-step explanation:

Given,

n = 100

Range of heights = 138 - 190cm

Range of weight = 39 to 150 kg

x' =167.46 cm

y' = 81.44 kg

r = 0.108

p value = 0.285

y = - 105 + 1.08x

Significance level = 0.05

We reject H0 since pvalue, 0.285 is less than significance level of 0.05.

Therefore,

Given height of adult male, x = 177 cm

y = - 105 + 1.08x

The best predicted value of y' =

y' = - 105 + 1.08(177)

y' = 86.16 kg

The best predicted value of y' is 86.16kg

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3 years ago
Solve each equation for p.<br> P+3/m=-1
Otrada [13]

Answer:

P= -m-3

I hope this helps!

3 0
3 years ago
The slope of a perpendicular line is the opposite reciprocal of the other slope.
Serjik [45]

Answer:it will probably be true

Step-by-step explanation:

It would probably be true.

7 0
3 years ago
C=5/9(F−32)
butalik [34]

Answer:

d

Step-by-step explanation:

5 0
3 years ago
Please help me!!!!!!!!!!!!!!
arsen [322]

Ans

184 sq meter

Step-by-step explanation:

Area of the cuboid box = (2*FA)+(2*SA)+(2*TA)

Where FA= Front face area

SA= Side face area

TA= top face are

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SA= 10*2= 20 sq meter

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7 0
3 years ago
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