The simplest form of an interest equation is A = P(1+rt)
where A = the total amount of money at the end, P = the principal (or amount of money you started with), r = the rate in percent, and t = the time in years.
In this case, P = 15000, r = 0.03 (because 3% in decimal form is 0.03), and t = 1:

So, after 1 year he will get $15450 back, making him $450 more.
Answer:
24
Step-by-step explanation:
Answer:
<em>Part A: 3,</em>
<em>Part B: - 4</em>
Step-by-step explanation:
<em>~ Part A ~ </em>
The problem would be in terms of such an expression: ( - 6 - ( - 3 )^2 )/ -5
Now knowing the expression, let us simplify in terms of basic algebra:
( -6 - 9 )/ -5 = ( - 15/ - 5 ) = <em>Answer; 3</em>
<em>~ Part B ~ </em>
We know the problem to be p^2/ r, but we must substitute the value of p being -10, and r ⇒ -25: ( - 10 )^2/ -25
Now let us simplify the expressions:
( - 10 )^2/ -25 = 100/ - 25 =<em> Answer; -4</em>
Answer:
In year 2013 annual maintenance done = $ 3,000,000
Out of this 85% is expected to renew in 2014 =
= $2,550,000
Now Sales in 2013 = $3,000,000
60% of these sales =
= $1,800,000
Now out of this 60%, 20% annual maintenance was expected to be paid
In 2014 =
= $360000
So, Total annual maintenance in 2014 = 
= $2,910,000
Answer:
they are directly proportional
so
5/22*7=1.59
he would finish in 1.59 min