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Svetlanka [38]
4 years ago
8

Evaluate 9-1/3 -2 1/3​

Mathematics
1 answer:
worty [1.4K]4 years ago
8 0

Answer:

i think its infinite solutions

Step-by-step explanation:

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Multiply: (x−5)(x−7) A x2−12x+35 B x2+2x+35 C x2+35 D x2+35x−12
ioda

Answer:

x^2 -12x+35

Step-by-step explanation:

(x−5)(x−7)

FOIL

first  x*x = x^2

outer -7x

inner -5x

last -7*-5 = 35

Add them together

x^2 -7x-5x +35

x^2 -12x+35

3 0
3 years ago
Read 2 more answers
What is the sixth term of (a - b)7?
yanalaym [24]
21a to the second and b to the 5
7 0
3 years ago
Angles α and β are the two acute angles in a right triangle. Use the relationship between sine and cosine to find the value of α
8_murik_8 [283]

Answer:

The value of angle α is 18 degree.

Step-by-step explanation:

Given information: Angles α and β are the two acute angles , α < β.

Given equation is

\sin (2x-8)=\cos (6x-6)

\cos (90-(2x-8))=\cos (6x-6)        [\because \sin (90-x)=\cos x]

Equating both sides.

90-2x+8=6x-6

98+6=6x+2x

104=8x

13=x

The value of x is 13.

The measure of angles is

2x-8=2(13)-8=18

6x-6=6(13)-6=72

Since 18<72, therefore the value of angle α is 18 degree.

8 0
4 years ago
Use the long division method to find the result when 6x^3+17x^2+19x+28 is divided by 3x+7.
kari74 [83]

Answer:

2x^2 + x + 4

Step-by-step explanation:

Use Polynomial division.

4 0
3 years ago
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Here are the monthly charges for Jo's mobile phone
Sindrei [870]
Jo's Mobile Plan:
Fixed monthly charge = £16
Monthly 150 free minutes, post that 13p (or £0.13) per minute,
Monthly 150 free texts, post that 15p (or £0.15) per text
Jo's mobile phone usage details:
170 minutes of calls
182 texts
Total Charges for Jo = Fixed Monthly Charge + Charges for Calls + Charges for Texts
⇒ Total Charges for Jo = 16 + (170-150) × 0.13 + (182-150) × 0.15
⇒ Total Charges for Jo = 16 + (20) × 0.13 + (32) × 0.15
⇒ Total Charges for Jo = 16 + 2.6 + 4.8
⇒ Total Charges for Jo = 23.4
Hence, Jo should be charged £23.4 for the month.

Hope this helps !
8 0
3 years ago
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