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3 years ago

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Using the formula A = l w, determine the area of a rectangle when l = 3.7 and w = 4. Group of answer choices A.) 4.1 B.) 7.7 C.)

12.7 D.) 14.8

1 answer:

sesenic [268]3 years ago

8 0

Answer:

D 14.8

Step-by-step explanation:

A=L*W which means length times width. 3.7x4= 14.8

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The amount of money in a bank account increased by 21.5% over the last year. if the amount of money at the beginning of the year

OLga [1]

Answer:

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Step-by-step explanation:

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3 years ago

Which of the following is a true statement describing the pattern 20, 25, 30, 35,…? The pattern contains only even numbers. The

evablogger [386]

In this pattern all are divisible by 5

20 $=4×5$ i.e. divisible by 5

25 $= 5×5$ is divisible by 5

30 $=2×3×5$ is divisible by 5

35 $=7×5$ is divisible by 5

Hence the pattern contain factor 5

6 0

3 years ago

Half of a number,increased by 4,is 18, what is that number

Drupady [299]

Answer:28

Step-by-step explanation:

28/2=14

14+4=18

8 0

4 years ago

Read 2 more answers

HELP ME ASAP! Will give BRAINLIEST! Please read the question THEN answer correctly! No guessing. Check ALL that apply

sammy [17]

Answer:

C. 65

Step-by-step explanation:

Compare to the standard form ...

ax² +bx +c

to find the values of a, b, c. They are ...

a=2, b=3, c=-7

The discriminant is ...

d = b² -4ac

d = (3)² -4(2)(-7) = 9 +56

d = 65 . . . . . . matches choice C

4 0

3 years ago

Jan'ai was asked to determine the minimum for a function with zeros located at –1 and 5, which also has a y-intercept of (0, –25

sergey [27]

The first error in Jan'ai's work in determining the considered function is given by: Option D: She incorrectly determined the x-coordinate of the vertex.

<h3>What are the coordinates of vertex for a quadratic function?</h3>

For a quadratic function of the form $y = ax^2 + bx + c$ , its vertex form is obtained as:

$y = ax^2 + bx + c\\y =a(x^2 + bx/a) + c\\y = a(x^2 + 2(b/2a)x + (b/2a)^2 -(b/2a)^2 )+ c\\y = a(x^2 + 2(b/2a)x + (b/2a)^2) -a \times (b/2a)^2 + c\\\\y = a(x+b/2a)^2 - a \times (b/2a)^2 + c$

For the form $y = a(x-h)^2 + k$ , the vertex has coordinates (h, k)

Thus, for the obtained equation $y = a(x+b/2a)^2 - a \times (b/2a)^2 + c$ , we get the coordinates of vertex as:

$h = -b/2a$ , $k = c - a\times(b/2a)^2$

Thus, the coordinates of vertex of $y = ax^2 + bx + c$ is:

$(h,k) = (-b/2a, c - a \times (b/2a)^2 )$

The missing steps of work of Jan'ai are:

Begin to write a function in factored form. $f(x) = a(x+1)(x-5)$
Substitute x = 0, y = f(x) = -25 to determine a. $-25 = a(0+1)(0-5)$
Simplify and solve to find a. $a=5$
Rewrite the function. $f(x) = 5(x+1)(x-5)$
Rewrite in standard form. $f(x) = 5x^2-20x-25$
Find the x-coordinate of the vertex. $x = -20/2(5) = -20/10; x = -2$
Find the y-coordinate of the vertex.

$y = 5x^2-20x-25$

$y = 5(-2)^2-20(-2)-25$

$y = 35$

so (-2,35) is the coordinate of the vertex, which denotes the minimum.

So, as we see, in the 5th step, Jan'ai had the quadratic function $f(x) = 5x^2-20x-25$ ,

Comparing this to $f(x) = ax^2 + bx + c$ , we get a = 5, b = -20, c = -25

The vertex's x-coordinate will be on -b/2a = -(-20)/ 2(5) = 20/10 = 2

But Jan'ai didn't putted that negative sign before b. in the 6th step.

Thus, the first error in Jan'ai's work in determining the considered function is given by: Option D: She incorrectly determined the x-coordinate of the vertex.

Learn more about the vertex form of a quadratic equation here:

brainly.com/question/9912128

6 0

3 years ago