Answer:Mark Is 9 years old; Christine is 5 years old
Step-by-step explanation:
Present age
LET mark age be x
Christine be x-4 yrs
In 3 yrs Time
Mark will be x+3 yrs old
Christine will be (x -4 +3) = x-1 years old
Also, In 3 years time
Christine = 2/3 Mark
such that
x-1 = 2/3(x+3)
x -1= 2x+6 / 3
3x -3= 2x+6
3X--2X = 6+3
=X=9
Mark Is 9 years old
Christine is x -4 = 9-4=5 years old
Factor out the GCF. Do not forget to include the GCF as part of your final answer. In this case, the three terms have a 3x in common, which leaves: Step 3: Multiply the leading coefficient and the constant, that is multiply the first and last numbers together.
Answer:
The answer is 364. There are 364 ways of choosing a recorder, a facilitator and a questioner froma club containing 14 members.
This is a Combination problem.
Combination is a branch of mathematics that deals with the problem relating to the number of iterations which allows one to select a sample of elements which we can term "<em>r</em>" from a collection or a group of distinct objects which we can name "<em>n</em>". The rules here are that replacements are not allowed and sample elements may be chosen in any order.
Step-by-step explanation:
Step I
The formula is given as

n (objects) = 14
r (sample) = 3
Step 2 - Insert Figures
C (14, 3) =
= 
= 
= 
= 364
Step 3
The total number of ways a recorder, a facilitator and a questioner can be chosen in a club containing 14 members therefore is 364.
Cheers!
6/10
300/500
30/50
60/100
12/20
Answer:
x=9
Step-by-step explanation:
Since you don't have that much information, you have to assume line HE is congruent to line GF, so now you have an equation that looks like this: 23=x+14. Now you subtract 14 from both sides giving you 9=x, and since you cannot simplify even further, that is your answer