All categories

3 years ago

Can -62 be classified as a natural number

1 answer:

katrin2010 [14]3 years ago

7 0

No, -62 can't be classified as a natural number because natural numbers are the ones used for counting (1,2,3, etc.) Natural numbers are all positive numbers except for zero.

You might be interested in

I need help with this question I don't know if you can see it

Dovator [93]

$\begin{gathered} (-5,-6)\Rightarrow C \\ (1,-7)\Rightarrow K \\ (4,4)\Rightarrow A \\ (-6,-2)\Rightarrow F \\ \text{Star}\Rightarrow(-9,3) \\ Heart\Rightarrow(-5,-9) \\ \text{Lightning}\Rightarrow(3,-8) \\ Triangle\Rightarrow(1,-8) \end{gathered}$

5 0

1 year ago

Larry was paid a total of $30 for raking leaves for 8 hours of work. This rate is constant. What will be the total amount that L

adelina 88 [10]

Answer:

Hi! The correct answer is $75 for 20 hours.

Step-by-step explanation:

7 0

3 years ago

Two brands of AAA batteries are tested in order to compare their voltage. The data summary can be found below.

garik1379 [7]

Answer:

The 95% confidence interval would be given by $0.281 \leq \mu_1 -\mu_2 \leq 0.529$

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X_1 =9.2$ represent the sample mean 1

$\bar X_2 =8.8$ represent the sample mean 2

n1=27 represent the sample 1 size

n2=30 represent the sample 2 size

$\sigma_1 =0.3$ population standard deviation for sample 1

$\sigma_2 =0.1$ population standard deviation for sample 2

$\mu_1 -\mu_2$ parameter of interest.

Solution to the problem

The confidence interval for the difference of means is given by the following formula:

$(\bar X_1 -\bar X_2) \pm z_{\alpha/2}\sqrt{\frac{\sigma^2_1}{n_1}+\frac{\sigma^2_2}{n_2}}$ (1)

The point of estimate for $\mu_1 -\mu_2$ is just given by:

$\bar X_1 -\bar X_2 =9.2-8.8=0.4$

Since the Confidence is 0.95 or 95%, the value of $\alpha=0.05$ and $\alpha/2 =0.025$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.025,0,1)".And we see that $t_{\alpha/2}=1.96$

Now we have everything in order to replace into formula (1):

$0.4-1.96\sqrt{\frac{0.3^2}{27}+\frac{0.1^2}{30}}=0.281$

$0.4+1.96\sqrt{\frac{6^2}{36}+\frac{7^}{49}}=0.519$

So on this case the 95% confidence interval would be given by $0.281 \leq \mu_1 -\mu_2 \leq 0.529$

6 0

3 years ago

-9=-3(x+2)<br>solve for x <br>show steps

lianna [129]

SimplifyOkie dokie so first things first, you have to get rid of those parentheses! To do this you use the distributive property. -3(x+2) is the same thing as -3(x)+-3(2). that and you get -9=-3x-6. So you want to get x by itself to be able to find what x is, so you add 6 to both sides of the equation to get rid of the -6. So then you get -3=-3x. Then you must divide both sides by the coefficient of x, which would be -3. When you divide both sides by -3 you get -3/-3=x, which is the same thing as 1=x. Hope this helped!

4 0

3 years ago

Read 2 more answers

There are 42 lorries, 54 cars and 284 motorbikes on a ferry.

fiasKO [112]

Answer:

x = 27

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers