Line JK passes through points J(–3, 11) and K(1, –3). What is the equation of line JK in standard form?
2 answers:
Determinante:
x....y....1
-3..11...1
1...-3....1
11x+y+9+3x+3y-11 = 0
11x+3x+y+3y+9-11 = 0
14x+4y-2 = 0
4y = -14x + 2
y = (-14x + 2)/4
y = (-7x+1)/2
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Answer:
Step-by-step explanation:
2x+3x=4
5x=4
x=4/5
Answer:
3y+30
Step-by-step explanation:
The answer is B (-3).
-2+3n>-14
+2 +2
3n>-12
n>-4
So yah.. perimeter of triangle b is
= 32 + a/2
