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gavmur [86]
3 years ago
5

Line JK passes through points J(–3, 11) and K(1, –3). What is the equation of line JK in standard form?

Mathematics
2 answers:
Lubov Fominskaja [6]3 years ago
8 0
(-3, 11)+(1, -3)=(-2, 8)
RSB [31]3 years ago
5 0
Determinante:
x....y....1
-3..11...1
1...-3....1

11x+y+9+3x+3y-11 = 0
11x+3x+y+3y+9-11 = 0
14x+4y-2 = 0

4y = -14x + 2
y = (-14x + 2)/4
y = (-7x+1)/2
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Can someone please help me
djyliett [7]

Slope = (10 - 5)/(-9 + 15) = 5/6

y = mx + b where m = slope and b = y-intercept

b = y - mx

b = 5 - (5/6) (-15)

b = 5 +12.5

b = 17.5

Equation y = 5/6 x + 17.5

Y-intercept = 17.5

X-intercept when y = 0

So

5/6 x + 17.5 = 0

5/6 x = -17.5

x = (-17.5) (6/5)

x = -21

Answer

Y intercept (0, 17.5 )

X intercept (-21 , 0)

3 0
3 years ago
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Lostsunrise [7]
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What is the value of the natural logarithm when x =0.6 is rounded to the nearest hundredth
Bezzdna [24]
We are tasked to determine the natural logarithm when x = 0.6. 
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ln x = ln 0.6 using a scientific calculator, enter ln 0.6 and then this would give an answer of -0.5108256238
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Which is the equation in Point-slope form of the line with a slope of 2 and passing thru the point (2,1)
KIM [24]

Answer:

y - 1 = 2(x - 2)

General Formulas and Concepts:

<u>Algebra I</u>

Point-Slope Form: y - y₁ = m(x - x₁)

  • x₁ - x coordinate
  • y₁ - y coordinate
  • m - slope

Step-by-step explanation:

<u>Step 1: Define</u>

Slope <em>m</em> = 2

Point (2, 1)

<u>Step 2: Write Equation</u>

  1. Substitute in variables:                       y - 1 = 2(x - 2)
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Mkey [24]

Answer:

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