Question

Line JK passes through points J(–3, 11) and K(1, –3). What is the equation of line JK in standard form?

Answer 1

(-3, 11)+(1, -3)=(-2, 8)

Answer 2

Determinante:
x....y....1
-3..11...1
1...-3....1

11x+y+9+3x+3y-11 = 0
11x+3x+y+3y+9-11 = 0
14x+4y-2 = 0

4y = -14x + 2
y = (-14x + 2)/4
y = (-7x+1)/2