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Fittoniya [83]
2 years ago
5

Let f(x)=2x^3-4x+1. Fill in the blank with the number of times the output value (y) occurs for input values of x between -3 and

3 (options listed in answer bank). Graph on your calculator in an appropriate window so you can count how many times.

Mathematics
1 answer:
Rasek [7]2 years ago
5 0
I found the options related to your question.

With the graph of the function, we can see    (x between -3 and 3)

y = 3, occurs...................3 times 

y = 1, occurs...................3 times 

y = 4, occurs...................1 time 

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What is the square root of 316
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Answer:

17.7763888346

Step-by-step explanation:

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2 years ago
Box a cost $5.25 for 250g and box b cost $4.50 for 375g what box is cheaper per gram and how much cheaper is it
kotegsom [21]

Answer: Box B

Step-by-step explanation:

Box A is 0.021 dollars per gram

Box B is 0.012 dollars per gram

Box B is cheaper per gram by 0.009 dollars

7 0
3 years ago
Use the general slicing method to find the volume of the following solids. The solid whose base is the region bounded by the cur
Y_Kistochka [10]

Answer:

The volume is V=\frac{64}{15}

Step-by-step explanation:

The General Slicing Method is given by

<em>Suppose a solid object extends from x = a to x = b and the cross section of the solid perpendicular to the x-axis has an area given by a function A that is integrable on [a, b]. The volume of the solid is</em>

V=\int\limits^b_a {A(x)} \, dx

Because a typical cross section perpendicular to the x-axis is a square disk (according with the graph below), the area of a cross section is

The key observation is that the width is the distance between the upper bounding curve y = 2 - x^2 and the lower bounding curve y = x^2

The width of each square is given by

w=(2-x^2)-x^2=2-2x^2

This means that the area of the square cross section at the point x is

A(x)=(2-2x^2)^2

The intersection points of the two bounding curves satisfy 2 - x^2=x^2, which has solutions x = ±1.

2-x^2=x^2\\-2x^2=-2\\\frac{-2x^2}{-2}=\frac{-2}{-2}\\x^2=1\\\\x=\sqrt{1},\:x=-\sqrt{1}

Therefore, the cross sections lie between x = -1 and x = 1. Integrating the cross-sectional areas, the volume of the solid is

V=\int\limits^{1}_{-1} {(2-2x^2)^2} \, dx\\\\V=\int _{-1}^14-8x^2+4x^4dx\\\\V=\int _{-1}^14dx-\int _{-1}^18x^2dx+\int _{-1}^14x^4dx\\\\V=\left[4x\right]^1_{-1}-8\left[\frac{x^3}{3}\right]^1_{-1}+4\left[\frac{x^5}{5}\right]^1_{-1}\\\\V=8-\frac{16}{3}+\frac{8}{5}\\\\V=\frac{64}{15}

5 0
3 years ago
I need help with Function Operations please
Alex787 [66]

Answer:

  30

Step-by-step explanation:

The ring operator signifies a composition of functions. The composition is evaluated right-to-left. That means the composition ...

  (f\circ g)(x)

should be interpreted to mean ...

  f(g(x))

___

To evaluate f(g(6)), we first evaluate g(6):

  g(6) = 6² -5 = 31

Then we evaluate the function f using that as its argument:

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3 0
2 years ago
70 - q - q - 2q = 80???
Aneli [31]


70-q-q-2q= 80

combine like terms first

so you get 70-4q= 80

subtract 70 on both sides and you get -4q= 10

divide -4 on both sides and you get q= 10/-4 or -2.5

3 0
3 years ago
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