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3 years ago

12

3x^2+16x^2+x+7-10x^2+22+15x-6x

1 answer:

lord [1]3 years ago

3 0

Answer:

9x^2 + 10x + 29

Step-by-step explanation:

Let's sort the x^2, the x and the numbers without an x:

First, the x^2

3x^2 + 16x^2 - 10x^2

So that's 3 + 16 - 10 if we ignore the x^2.

We can simplify this to 9x^2, because 3+16-10=9.

The same for the x:

1x + 15x - 6x = 10x

And then there's the lone 7 and 22.

7 + 22 = 29

So to summarize:

9x^2 + 10x + 29

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Alex Ar [27]

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3 years ago

2 (3x+1)=17-3 (x-17)

elena-14-01-66 [18.8K]

<h2>Answer:</h2>

$x = \frac{22}{3}$

<h3>alternative form:</h3>

$x = 7 \frac{1}{3} \: or \: x = 7.33333333333$

<h2>Step-by-step explanation:</h2>

$2(3x + 1) = 17 - 3( x - 17) \\ distribute \\ \\ 6x + 2 = 17 - 3x + 51 \\ add \: 3x \: from \: both \: sides \\ \\ 9x + 2 = 17 + 51 \\ add \: 17 \: to \: 51 \\ \\ 9x + 2 = 68 \\ subtract \: 2 \: from \: both \: sides \\ \\ 9x = 66 \\ divide \: both \: sides \: by \: 9 \\ \\ x = \frac{22}{3}$

3 0

3 years ago

1. Mark and Bill have a combined weight of 170

qwelly [4]

<h3>Equation : x + y = 170 and y = 2x - 40</h3><h3>The weight of Bill is 70 pounds and weight of mark is 100 pounds</h3>

<em><u>Solution:</u></em>

Let the weight of Bill be "x"

Let the weight of mark be "y"

Given that,

Mark and Bill have a combined weight of 170 pounds

Therefore,

x + y = 170 ------- eqn 1

Mark weighs 40 pounds less than twice Bill's weight

y = 2x - 40 ------- eqn 2

<em><u>Substitute eqn 2 in eqn 1</u></em>

x + 2x - 40 = 170

3x = 170 + 40

3x = 210

x = 70

<em><u>Substitute x = 70 in eqn 2</u></em>

y = 2(70) - 40

y = 140 - 40

y = 100

Thus weight of Bill is 70 pounds and weight of mark is 100 pounds

6 0

3 years ago

What is the area of a rectangle with vertices at (4, 3), (11, 3), (11, 9), and (4, 9)?

Brums [2.3K]

Answer:

The area of a rectangle is 42 units ².

Step-by-step explanation:

As the diagram is given below.

Distance Formula

$Distance\ formula = \sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}$

As the rectangle with vertices at A (4, 3), B(11, 3),C (11, 9), and D (4, 9).

Take A (4, 3) to B(11, 3)

$AB = \sqrt{(11-4)^{2}+(3-3)^{2}}$

$AB = \sqrt{(7)^{2}+(0)^{2}}$

$AB = \sqrt{49}$

$\sqrt{49} =7$

AB = 7 units

As take B(11, 3) to C (11, 9).

$BC = \sqrt{(11-11)^{2}+(9-3)^{2}}$

$BC = \sqrt{(0)^{2}+(6)^{2}}$

$BC = \sqrt{36}$

$\sqrt{36} =6$

BC = 6 units

As take C (11, 9) toD (4, 9).

$CD = \sqrt{(4-11)^{2}+(9- 9)^{2}}$

$CD = \sqrt{(7)^{2}+(0)^{2}}$

$CD = \sqrt{49}$

$\sqrt{49} =7$

CD = 7 units

As take D (4, 9) to A (4, 3)

$DA = \sqrt{(4-4)^{2}+(3-9)^{2}}$

$DA = \sqrt{(0)^{2}+(-6)^{2}}$

$DA = \sqrt{36}$

$\sqrt{36} =6$

DA = 6 units

Thus

AB = DC= 7 units

AD = BC = 6 units

Formula

Area of rectangle = Length × Breadth

Length = 7 units

Breadth = 6 units

Put value in the above

Area of rectangle = 7 × 6

= 42 units ²

Therefore the area of a rectangle is 42 units ².

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3 years ago

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aev [14]

the answer would (d) graph D

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3 years ago

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