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Fiesta28 [93]
3 years ago
15

Joe is 6 feet tall and cast a 3 foot shadow. He is standing next to a building that cast a shadow that is 20 feet long. How tall

is the building.​
Mathematics
2 answers:
masha68 [24]3 years ago
4 0

Answer:

40 feet

Step-by-step explanation:

lorasvet [3.4K]3 years ago
4 0

Answer:

40 feet tall

Step-by-step explanation:

6/2 =3

?/2 =20

*2    *2

? = 40

you do inverse operations because 6 divided by 2 is 3... the ? is the variable for how tall the building is... ? divided by 2 = 20 so you multiply 2 and 20 to get the total height

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True or False:<br><br>cot = 1/tan
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The perimeter of a rectangular garden is 43.8 feet. It’s length is 12.4 feet. What is it’s width?
Stells [14]

Answer:

9.5 m

Step-by-step explanation:

If width is -- x

12.4 + x + 12.4 + x = 43.8

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8 0
3 years ago
g If a random sample of 18 deliveries was selected instead and the standard deviation of these delivery times was found to be 9.
lana [24]

Answer:

We can use the z score formula given by:

z= \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}

If we use this formula we got:

z=\frac{21-20}{\frac{9.31}{\sqrt{18}}}= 0.456

z=\frac{25-20}{\frac{9.31}{\sqrt{18}}}= 2.279

And using a calculator, excel or the normal standard table and we have that:

P(0.456

Step-by-step explanation:

We assume this previous info:  It is known that the amounts of time required for room-service delivery at a certain Marriott Hotel are Normally distributed with the average delivery time of 20 minutes.

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Let X the random variable that represent the delivery times of a population, and for this case we know the distribution for X is given by:

X \sim N(20,9.31)  

Where \mu=20 and \sigma=9.31

Since the distribution for X is normal then the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

And we can use the z score formula given by:

z= \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}

If we use this formula we got:

z=\frac{21-20}{\frac{9.31}{\sqrt{18}}}= 0.456

z=\frac{25-20}{\frac{9.31}{\sqrt{18}}}= 2.279

And using a calculator, excel or the normal standard table and we have that:

P(0.456

6 0
4 years ago
5. A scientist believes the concentration of radon gas in the air is greater that the established safe level of 4pci or less. Th
zysi [14]

Complete Question

A scientist believes the concentration of radon gas in the air is greater that the established safe level of 4 pci or less. The scientist tests the composition for 36 days finding an average concentration of 4.4 pci with a sample standard deviation of 1 pci.

a) In testing the scientist's belief, write the appropriate hypotheses:

           H_o:                   Ha:

b) What decision should be made?

Answer:

a

The null hypothesis is  H_o :  \mu  \le  4 \  pci

The  alternative  hypothesis is H_a  :  \mu  >  4 \ pci

b

There is sufficient evidence to conclude that the concentration of radon gas in the air is greater that the established safe level of 4pci or less

Step-by-step explanation:

From the question we are told that

   The population mean is  \mu  =  4 \ pci

    The sample size n  =  36 \ days

     The  sample  mean is  \= x  =  4.4 \  pci

     The  standard deviation is  \sigma  =  1 \ pci

       The  level  of significance is  \alpha =  0.05

The null hypothesis is  H_o :  \mu  =  4 \  pci

The  alternative  hypothesis is H_a  :  \mu  >  4 \ pci

  Generally the test statistics is mathematically represented as

          t =  \frac{ \= x  -  \mu }{ \frac{ \sigma}{ \sqrt{n} } }

=>      t =  \frac{ 4.4  -  4 }{ \frac{ 1}{ \sqrt{36} } }

=>      t =  \frac{ 4.4  -  4 }{ \frac{ 1}{ \sqrt{36} } }

=>      t =2.4

The  p-value  is mathematically represented as

      p-value  =  P(Z >  2.4  )

From the  z-table  

          P(Z >  2.4  )  =  0.008

    p-value  =0.008

So from this obtained value  we see that

     p-value <  \alpha so we reject the null hypothesis

Hence we can conclude that there is sufficient evidence to conclude that the concentration of radon gas in the air is greater that the established safe level of 4pci or less

4 0
3 years ago
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