Answer:
(c-a, 0)
Step-by-step explanation:
The horizontal space between (c, b) and P is the same as the space between (a, b) and O.
Coordinates are written (x, y), where x is for horizontal space.
P is on the x-axis, making the y-coordinate 0.
(a+c, 0) would be to the right of the entire parallelogram.
(c, 0) would be directly below (c, b).
(a-c, 0) would be to the left of the entire parallelogram and in the other quadrant.
What I did is to add 0.52
+0.15
then try to find what could equal the same amount with 0.52
Answer:
third option
Step-by-step explanation:
Given
3 ![\left[\begin{array}{ccc}-2&5\\1&0\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-2%265%5C%5C1%260%5C%5C%5Cend%7Barray%7D%5Cright%5D)
Multiply each element in the matrix by 3
= ![\left[\begin{array}{ccc}3(-2)&3(5)\\3(1)&3(0)\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D3%28-2%29%263%285%29%5C%5C3%281%29%263%280%29%5C%5C%5Cend%7Barray%7D%5Cright%5D)
=
Since the area of a square is equal to the square of one of its side's length, then the area should be equivalent to

.

---> equation (1)
By using pythagoras rule which states that the

---> equation (2)
where the opposite side's length is 8 and the hypotenuse side's length is 10
by substituting by the values in equation (2) therefore,

substitute this value in equation (1) then

where A is the area of the square whose side is x