Answer:
ΔNAS≅ΔSEN by SSA axiom of congruency.
Step-by-step explanation:
Consider ΔNAS and ΔSEN,
NS=SN(Common ie . Both are the same side)
SA=NE( Given in the question that SA≅ NE)
∠SNA=∠NSE( Due to corresponding angle property where SE ║ NA)
Therefore, ΔNAS ≅ΔSEN by SSA axiom of congruency.
∴ NA≅SA by congruent parts of congruent Δ. Hence, proved.
Answer:
148
Step-by-step explanation:
an outlier is somthin that stands out
Hello,
Sorry,
The true conjecture should have been |n|>=0
Answer B
0 is also negative
Answer:
29 square = 20 square+ b square
b= 21
The y intercept is +4 as the line crosses at y=4
