3 years ago

the axis of symmetry for a function in the form f(x)=x^2+4x-5 is x=-2. what are the coordinates of the vertex of the graph?

1 answer:

4 0

Hello :
<span>f(x)=x²+4x-5
</span><span>The axis of symmetry for a function in the form f(x)=x^2+4x-5 is x=-2 :
</span>f(x) = (x+2)² + b
f(x) x²+4x+4+b= x² +4x-5
4+b= -5
b = -9
the vertex is : (2 , -9)

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