Answer:
A regular 12-oz beer is about 5% alcohol. This works out to about 14.03 grams of alcohol per beer. If the driver drank two beers, how many grams of alcohol did he consume? <u>28.06 grams</u>
The driver weighs about 160 lbs. What is his body weight in kg? What is his body volume in mL? (1 lb = 0.45 kg) (1 kg = 1000 mL) <u>72.57 kg/72,560 mL</u>
For most males, 68 percent of the body is water. What is the volume of water in the driver’s body in mL? <u>49,350 mL</u>
Use the above information to calculate BAC. <u>0.0569%</u>
The measured BAC was 0.12%. Was the driver telling the truth about how much he drank? Calculate the difference between the two BAC percentages. <u>No. 0.0569% is different.</u>
If the driver had really consumed only two beers, would he have been arrested for DUI? Explain. <u>The driver would not have been arrested if he only had two beers. He more or less had more than two beers in his car when the police checked his car.</u>
Step-by-step explanation:
the underlined areas are your answers.
Answer:
375 fishes
Step-by-step explanation:
12000 divided by 2 is 6000 1st year
6000 divided by 2 is 3000 2nd year
3000 divided by 2 is 1500 3rd year
1500 divided by 2 is 750 4th year
750 divided by 2 is 375 5th year
Answer:
The probability is 
Step-by-step explanation:
From the question we are told that
The probability of the television passing the test is p = 0.95
The sample size is n = 10
Generally the comprehensive testing process for all essential functions follows a binomial distribution
i.e
and the probability distribution function for binomial distribution is
Here C stands for combination hence we are going to be making use of the combination function in our calculators
Generally the probability that at least 9 pass the test is mathematically represented as
=> ![P(X \le 9) = [^{10}C_9 * (0.95)^9 * (1- 0.95)^{10-9}]+ [^{10}C_{10} * {0.95}^{10} * (1- 0.95)^{10-10}]](https://tex.z-dn.net/?f=P%28X%20%5Cle%209%29%20%3D%20%5B%5E%7B10%7DC_9%20%2A%20%20%280.95%29%5E9%20%2A%20%20%281-%200.95%29%5E%7B10-9%7D%5D%2B%20%5B%5E%7B10%7DC_%7B10%7D%20%2A%20%20%7B0.95%7D%5E%7B10%7D%20%2A%20%20%281-%200.95%29%5E%7B10-10%7D%5D)
=> ![P(X \le 9) = [10 * 0.6302 * 0.05 ]+ [1 *0.5987 * 1 ]](https://tex.z-dn.net/?f=P%28X%20%5Cle%209%29%20%3D%20%5B10%20%2A%20%200.6302%20%20%2A%200.05%20%5D%2B%20%5B1%20%2A0.5987%20%2A%201%20%5D%20)
=>
T= sqrt(5/wc)
remove ( )
T= 5sqrt/wc
multiply by wc
Twc=5sqrt
divide by Tc
W= 5sqrt/cT
hope this helps
