A student can take three subjects in 40 ways.
<u>SOLUTION:</u>
Given that, there are 4 different math courses, 5 different science courses, and 2 different history courses.
A student must take one of each, how many different ways can this be done?
Now, number ways to take math course = 4
Number of ways to take science course = 5
Number of ways to take history course = 2
So, now, total possible ways = product of possible ways for each course = 4 x 5 x 2 = 40 ways.
Hence, a student can take three subjects in 40 ways.
Answer:
Step-by-step explanation:

Answer:
Option D, 
Step-by-step explanation:
<u>Step 1: Multiply</u>
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Answer: Option D, 
The equation to find percent error is:
percent error=(experimental-theoretical)/theoretical *100
So, (115-82.5)/82.5=0.393939*100
39.3939%, or 39.94%
Hope this helps!!
Step-by-step explanation:
Length = L
Width = W
L=8 more than 2W
L = 8 * 2W
L = 16W
Perimeter = 96
perimeter is the lengths of all sides added together
so
2L + 2W = 96
we have
L = 16W
2L + 2W = 96
let's do substitution
put what L = into 2L + 2W = 96
so
2(16W) + 2W = 96
can you rearrange that to get w
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