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3 years ago

What is the range of this set of data? 111, 97, 63, 84, 100, 119, 72

Mathematics

2 answers:

melisa1 [442]3 years ago

6 0

Answer:

Step-by-step explanation:

Given is the data set:

111, 97, 63, 84, 100, 119, 72

To find: Range of the given data set.

Solution:

Range of the data set is defined the difference of the highest data point and the lowest data point.

Thus, firstly arrange the given data set in ascending order, we have

63,72,84,97,100,111,119

Now, the highest term of the given data set is 119 and the lowest term is 63, thus range is given as:

$Range= Highest term-Lowest term=119-63=56$ .

Thus, range is 56.

White raven [17]3 years ago

5 0

The range is 119-63 = 56

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Stolb23 [73]

Answer:

Area of the sector = 29.48 square miles.

Step-by-step explanation:

Given:

Radius of a circle = 13 miles

Angle bounded by the arc = 20 deg

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Note: Area of a sector = $\frac{(\theta)}{360}\times \pi\times r^2$

Plugging the values in the equation.

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3 years ago

The roots of a quadratic equation ax2+bx+c=0 are 3+sqrt2 and 3−sqrt2. Find the values of b and c assuming that a=1.

slamgirl [31]

Answer:

$b=-6\\c=7$

Step-by-step explanation:

we know that

The general equation of a quadratic function in factored form is equal to

$y=a(x-x_1)(x-x_2)$

where

a is a coefficient of the leading term

x_1 and x_2 are the roots

we have

$a=1\\x_1=3+\sqrt{2}\\x_2=3-\sqrt{2}$

substitute

$y=(1)(x-(3+\sqrt{2}))(x-(3-\sqrt{2}))$

Applying the distributive property convert to expanded form

$y=x^2-x(3-\sqrt{2})-x(3+\sqrt{2})+(3+\sqrt{2})(3-\sqrt{2})$

$y=x^2-(3x-x\sqrt{2})-(3x+x\sqrt{2})+(9-2)$

$y=x^2-3x+x\sqrt{2}-3x-x\sqrt{2}+7$

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therefore

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3 years ago