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jeka57 [31]
3 years ago
11

How can you find the side of a triangle only using angles 33 degrease, 49 degrees, and 98 degrees, and one side which is 100m. I

only need to know the side opposite to 33 degrees but, I’ve been doing online school and my teacher can barely teach this is actually the most I’ve learned all year so I can’t ask him. If someone could help me out thank you so much!!

Mathematics
2 answers:
stellarik [79]3 years ago
8 0

Answer: x = 72.2

Step-by-step explanation: You have to use Law of Sines. If you don’t know what that is, it’s when you have sin times an angle measure divided by the opposite side length. You set up two of these and make them equal to each other with one unknown. (In this case it would be the side length. So, your equation would look like this: sin49 over 100 = sin33 over x. You are then tryin to solve for x. So, you can use cross multiplication to get

xsin49 = 100sin33. Then divide by sin49 to get x by itself. You would then have x = 100sin33 over sin49. Then you can use your calculator and plug it in to get 72.16 rounding it to 72.2.

kumpel [21]3 years ago
3 0

Answer:

72.17 m to the nearest hundredth.

Step-by-step explanation:

It is sin not cos.

We use the Sine Rule to do this

a / sin A = b / sin C = c / sin C.

Here we have:

100 / sin 49 =  x / sin 33

x =  100 * sin 33 / sin 49

= 72.17 m.

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aksik [14]
A combination is an unordered arrangement of r distinct objects in a set of n objects. To find the number of permutations, we use the following equation:

n!/((n-r)!r!)

In this case, there could be 0, 1, 2, 3, 4, or all 5 cards discarded. There is only one possible combination each for 0 or 5 cards being discarded (either none of them or all of them). We will be the above equation to find the number of combination s for 1, 2, 3, and 4 discarded cards.

5!/((5-1)!1!) = 5!/(4!*1!) = (5*4*3*2*1)/(4*3*2*1*1) = 5

5!/((5-2)!2!) = 5!/(3!2!) = (5*4*3*2*1)/(3*2*1*2*1) = 10

5!/((5-3)!3!) = 5!/(2!3!) = (5*4*3*2*1)/(2*1*3*2*1) = 10

5!/((5-4)!4!) = 5!/(1!4!) = (5*4*3*2*1)/(1*4*3*2*1) = 5

Notice that discarding 1 or discarding 4 have the same number of combinations, as do discarding 2 or 3. This is being they are inverses of each other. That is, if we discard 2 cards there will be 3 left, or if we discard 3 there will be 2 left.

Now we add together the combinations

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-------------------------------

Note: There is also an equation for permutations which is:

n!/(n-r)!

Notice it is very similar to combinations. The only difference is that a permutation is an ORDERED arrangement while a combination is UNORDERED.

We used combinations rather than permutations because the order of the cards does not matter in this case. For example, we could discard the ace of spades followed by the jack of diamonds, or we could discard the jack or diamonds followed by the ace of spades. These two instances are the same combination of cards but a different permutation. We do not care about the order.

I hope this helps! If you have any questions, let me know :)








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3 years ago
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Heyo. Let's go ahead and set this problem up

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