Consider the length of diagonal is 8.5 cm instead of 8.5 m because length of perpendiculars are in cm.
Given:
Length of the diagonal of a quadrilateral = 8.5 cm
Lengths of the perpendiculars dropped on it from the remaining opposite vertices are 3.5 cm and 4.5 cm.
To find:
The area of the quadrilateral.
Solution:
Diagonal divides the quadrilateral in 2 triangles. If diagonal is the base of both triangles then the lengths of the perpendiculars dropped on it from the remaining opposite vertices are heights of those triangles.
According to the question,
Triangle 1 : Base = 8.5 cm and Height = 3.5 cm
Triangle 2 : Base = 8.5 cm and Height = 4.5 cm
Area of a triangle is
Using this formula, we get
and
Now, area of the quadrilateral is
Therefore, the area of the quadrilateral is 34 cm².
That day they will have 132 conversations. There are 12 members and each one will be calling the remaining 11 members of the club which means each one will make 11 calls and that will be done by 12 members so 11x12= 132 conversations in total
12 months= 1 year
Every month they make 132 calls so 132x12 will be 1,584 calls per year.
If the club decides to add four new members to the club the conversations each month will rise up to 240.
If the other club likes the idea they can use the following equation
(x-1)(x)
X represents the number of members of the group the subtraction of 1 is when a member makes a call not including them selves so there are 12 members but the one making the call isn't included so there are 11 calls being made then being multiplied by the total number of members.
(x-1)(x)
(12-1)(12)
11(12)
132
Answer:
-16
Step-by-step explanation:
it's right I promise
Answer:
A : 4x+5x=180
Step-by-step explanation:
They form a linear pair which equals 180.
363 rounded to the nearest ten would be 360
