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nasty-shy [4]
3 years ago
15

There are 575 fireworks to be shot off in a firework display every minute 12 new fireworks are shot off display write a verbal m

odel and algebraic expression to represent the number of fireworks
Mathematics
1 answer:
lukranit [14]3 years ago
8 0

Complete question :

There are 575 fireworks to be shot off in a firework display every minute 12 new fireworks are shot off display write a verbal model and algebraic expression to represent the number of fireworks left to be shot off after t minutes.

Answer:

575 - 12t

Step-by-step explanation:

Given the following :

Total number of fireworks = 575

Number of shots per minute = 12

To calculate the number of fireworks left to be shot off after t minutes, The total number of fireworks already shot after the same time interval t in minutes, is first obtained, this is equivalent to (12*t). The result is then subtracted from the total number of fireworks to be shof off.

In algebraic terms

[total number of fireworks on display - (number of shots per minute × t)]

575 - 12t

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1 cm = 5km

8.5 ÷ 5 = 1.7

There will be 1.7 centimeters between his house and school.

3 0
2 years ago
Jasper made a flag for his football team. He painted 1/2 of the flag blue and 1/2 of the flag yellow. He added stars to 1/3 of t
SVETLANKA909090 [29]

For this case we have that half of the flag was painted blue and the other half yellow.

In addition, a third of the blue half was covered with stars.

So:

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6 0
3 years ago
Please help me with steps.
laiz [17]

Answer:

I think its would be d

Step-by-step explanation:

the distributive property

8 0
3 years ago
Read 2 more answers
Plz help me solve this
posledela

1.-28×-28×-28+13×13×13+16×16×16

=21,952+2,197+4,096

=28,245.

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6 0
3 years ago
Y varies directly with x, and y = 5 when x = 4. What is the value of x when y = 8?
Tomtit [17]
As y varies directly with x, there is a proportionality constant. As x increases by that certain constant, y also increases. We equate:
y = kx
where k = proportionality constant.
Given the condition, y = 5 when x = 4, then we solve for k:
5 = k(4)
k = 5/4 or 1.25
When y = 8, then
8 = (5/4)(x)
x = 8/(5/4) = (8)(4/5) = 32/5 or 6.4 (ANSWER)
7 0
3 years ago
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