The probability that the first two electric toothbrushes sold are defective is 0.016.
The probability of an event, say E occurring is:
Here,
n (E) = favorable outcomes
N = total number of outcomes
Let X = the number of defective electric toothbrushes sold.
The number of electric toothbrushes that were delivered to a store is n = 20.
The number of defective electric toothbrushes is x = 3.
The number of ways to select two toothbrushes to sell from the 20 toothbrushes is:
The number of ways to select two defective toothbrushes to sell from the 3 defective toothbrushes is:
Compute the probability that the first two electric toothbrushes sold are defective as follows:
P (Selling 2 defective toothbrushes) = Favorable outcomes ÷ Total no. of outcomes
Thus, the probability that the first two electric toothbrushes sold are defective is 0.016.
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Hmm, this answer is mathematically incorrect. If the question has no errors, 38 can go into 7 0 times, it can't because its bigger than 7.
However, if it were meant to be the other way round, how many times does 7 go into 38, the answer would be 5.
Answer:
input: x+4 output (x,y)
-2 -2 + 4 =2 2 (-2,2)
0 0 + 4 = 4 4 (0,4)
2 2 + 4 = 6 6 (2,6)
...
Step-by-step explanation:
continue by plugging in x to the equation, x is input and y is output
then just plot your (x,y) points on the graph.