Answer:
![\displaystyle\frac{\sqrt[4]{3x^2}}{2y}](https://tex.z-dn.net/?f=%5Cdisplaystyle%5Cfrac%7B%5Csqrt%5B4%5D%7B3x%5E2%7D%7D%7B2y%7D)
Step-by-step explanation:
It can work well to identify 4th powers under the radical, then remove them.
![\displaystyle\sqrt[4]{\frac{24x^6y}{128x^4y^5}}=\sqrt[4]{\frac{3x^2}{16y^4}}=\sqrt[4]{\frac{3x^2}{(2y)^4}}\\\\=\frac{\sqrt[4]{3x^2}}{2y}](https://tex.z-dn.net/?f=%5Cdisplaystyle%5Csqrt%5B4%5D%7B%5Cfrac%7B24x%5E6y%7D%7B128x%5E4y%5E5%7D%7D%3D%5Csqrt%5B4%5D%7B%5Cfrac%7B3x%5E2%7D%7B16y%5E4%7D%7D%3D%5Csqrt%5B4%5D%7B%5Cfrac%7B3x%5E2%7D%7B%282y%29%5E4%7D%7D%5C%5C%5C%5C%3D%5Cfrac%7B%5Csqrt%5B4%5D%7B3x%5E2%7D%7D%7B2y%7D)
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The applicable rules of exponents are ...
1/a^b = a^-b
(a^b)(a^c) = a^(b+c)
The x-factors simplify as ...
x^6/x^4 = x^(6-4) = x^2
The y-factors simplify as ...
y/y^5 = 1/y^(5-1) = 1/y^4
The constant factors simplify in the usual way:
24/128 = (8·3)/(8·16) = 3/16
B). 10.63
Because 7^2=49 and 8^2=64 then 49+64=113 then the square root of 113 is 10.63
-4x/5≥1/10
-8x≥1
x≤-1/8
x∈(-∞;-1/8]
Answer:
9 and 18
Step-by-step explanation:
2x and x are the numbers
1/x-1/2x=1/18
2/2x-1/2x=1/18
1/2x=1/18
2x=18X=9,
2x=18
The two integers are 9 and 18