Okay, so what you need to figure out is that how many years in between 21 1/4 and 37 there are based on the amount the tree grows a year. So, 1 3/4 times 9 is 15.75, and this added to 21 1/4 is 37. This means that it will take the tree 9 years to grow from 21 1/4 ft to 37 ft.
Answer:84
Step-by-step explanation:
Okay. Are you taking calc? Dv/dt =d/dt(L(t)^3)=d/dt[(sqrt(14)+2t)^3]= 6(Sqrt(14)+2t)^2)=44. We defined t=0 to be time at which length is sqrt(14). Does that work?
First off, consecutive integer and can be written as n, n+1 and n+2
(try putting a number in for n if it does not make sense yet)
The sum of the first and twice the second would be n+2(n+1)
So, our equation becomes
n+2(n+1)=110-3(n+2)
n+2n+2=110-3n-6
3n+2=104
6n=102
n=17
so, our three term are 17,18 and 19
9514 1404 393
Answer:
t = 3-√7 and 3+√7 seconds after launch
Step-by-step explanation:
You want to find the values of t that make h=10.
10 = 30t -5t^2
t^2 -6t = -2 . . . . . divide by -5
t^2 -6t +9 = 7 . . . add 9 to complete the square
(t -3)^2 = 7 . . . . . write as a square
t -3 = ±√7 . . . . . . take the square root
t = 3 ±√7 . . . . . . values of t for which height is 10 meters
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These values are about 0.354 seconds, and 5.646 seconds.
