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4 years ago

How do I solve 16.08t^2 - 29.5t -7 =0

1 answer:

6 0

Use calculator
first press mode 3x
second press 1
third choose degree n press 2
forth put the equation
press equal for final
t=2.056
t=-0.213

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slava [35]

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3 years ago

Simplify 2 to the fifth power over 3 squared all raised to the fourth power. 2 to the twentieth power over 3 to the eighth power

Sunny_sXe [5.5K]

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Answer: 2 to the twentieth power over 3 to the eighth power

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3 years ago

Find an equation for the tangent to the curve at P and the horizontal tangent to the curve at Q. y = 5 + cot x - 2 csc x 0 1 2 3

oksian1 [2.3K]

Answer with explanation:

The given function in x and y is,

y= 5 +cot x-2 Cosec x

To find the equation of tangent, we will differentiate the function with respect to x

$y'= -\csc^2 x+2 \csc x\times \cot x$

Slope of tangent at (π/2,3)

$y'_{(\frac{\pi}{2},3)}= -\csc^2\frac{\pi}{2} +2 \csc \frac{\pi}{2}\times \cot \frac{\pi}{2}\\\\=-1+2\times 1 \times 0\\\\= -1$

Equation of tangent passing through (π/2,3) can be obtained by

$\rightarrow \frac{y-y_{1}}{x-x_{1}}=m(\text{Slope})\\\\ \rightarrow \frac{y-3}{x-\frac{\pi}{2}}=-1\\\\\rightarrow 3-y=x-\frac{\pi}{2}\\\\\rightarrow x+y-3-\frac{\pi}{2}=0$

⇒There will be no Horizontal tangent from the point (π/2,3).

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4 years ago

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4 years ago

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tamaranim1 [39]

False, they have a different slope and y intercept

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3 years ago

Read 2 more answers