Answer:
80%
Step-by-step explanation:
Given:
Team D used a recipe that consists of 20 cups of sand, 2 cups of flour, and 3 cups of water.
Question asked:
How does the percent of sand in Team D's recipe compare to that of the other teams ?
Solution:
Team D used a recipe that consists of sand = 20 cups
Team D used a recipe that consists of flour = 2 cups
Team D used a recipe that consists of water = 3 cups
Total number of cups together = 20 + 2+ 3 =25 cups
Now we will have to find percent of cups of sand out of the total number of cups.
By using formula of percentage,
Percent = 

Therefore, 80% of sand in Team D's recipe compare to that of the other teams.
If we increase q by 2, it means that q becomes q+2.
So, p will become

So, the new value for p is 6 more than the previous one.
The second exercise looks a bit odd: if the sequence started with -100, then it would be
-100, -97, -94, -91, -88,...
And every term would be 3 more than the previous one, so the next term would be -85, but this doesn't appear in your option.
Also, the fact that the sequence starts with positive 100 is quite strange, because it is unrelated to the rest of the sequence.
Are you sure that the exercise is written correct? Or are there any typos?
Answer:
$3200
Step-by-step explanation:
i had the answer but wanted to make sure
when added up everything equals 273,900
-700
--------
273,200
his networth is 270,000 that means when you subtract it from the 273,200 you are left with 3,200
Since each trial has the same probability of success,
Let, <span><span><span>Xi</span>=1</span></span> if the <span><span>i<span>th</span></span></span> trial is a success (<span>0</span> otherwise). Then, <span><span>X=<span>∑3<span>i=1</span></span><span>Xi</span></span><span>X=<span>∑<span>i=1</span>3</span><span>Xi</span></span></span>,
and <span><span>E[X]=E[<span>∑3<span>i=1</span></span><span>Xi</span>]=<span>∑3<span>i=1</span></span>E[<span>Xi</span>]=<span>∑3<span>i=1</span></span>p=3p=1.8</span><span>E[X]=E[<span>∑<span>i=1</span>3</span><span>Xi</span>]=<span>∑<span>i=1</span>3</span>E[<span>Xi</span>]=<span>∑<span>i=1</span>3</span>p=3p=1.8</span></span>
So, <span><span>p=0.6</span><span>p=0.6</span></span>, and <span><span>P{X=3}=<span>0.63</span></span><span>P{X=3}=<span>0.63</span></span></span>
I thought what I did was sound, but the textbook says the answer to (a) is <span>0.60.6</span> and (b) is <span>00</span>.
Their reasoning (for (a)) is as follows:
Answer:
Step-by-step explanation:
line perpendicular to ax+by=c is
bx-ay=k, where k is a constant.
if it passes through (-1,2) then
b(-1)-a(2)=k
or k=b-2a
so reqd. eq . is bx-ay=b-2a