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timurjin [86]
3 years ago
5

Please help if so thank you

Mathematics
1 answer:
soldi70 [24.7K]3 years ago
4 0

Answer:

\large\boxed{10t}

Step-by-step explanation:

Use:\\\\(a^n)^m=a^{nm}\\\\(ab)^n=a^nb^n

\Bigg[\bigg(1\underbrace{00,000,000}_{8}t^8\bigg)^{-\frac{1}{2}}\Bigg]^{-\frac{1}{4}}=\bigg(10^8t^8\bigg)^{\left(-\frac{1}{2}\right)\left(-\frac{1}{4}\right)}=\bigg(10t\bigg)^{8\left(\frac{1}{8}\right)}=\bigg(10t\bigg)^1


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