According to your text first equation is
y = 3x+2
second equation is
y = Ix-1I + 1
Definition of our absolute value Ix-1I is
1) we take x-1 with condition x-1≥0 => x≥1
2) we take -(x-1) = -x+1 with x<1
Let's form the first system with condition x≥1
y= 3x+2 and y=x-1+1=> y=x
If the left sides of the equations are equal, than the right sides are equal too
3x+2=x => 3x-x=-2 => 2x=-2 => x=-1
This solution we can't accept because it does not meet the condition
x≥1
Lets's form the second system with condition x<1
y=3x+2 and y= -x+1+1 =. y = -x+2
In the same way as previous the right sides are equal =>
3x+2=-x+2 => 3x+x = +2-2 => 4x=0 => x=0
We accept this solution bacause its meet with condition x<1
When we replace this solution in equation y=3x+2 we got
y=3*0+2=2 Only one solution is (x,y) = (0,2)
Good luck !!!!!
Answer:
(-3/2)x + 9
Step-by-step explanation:
The inverse function of h(x) = (-2/3)x + 6 is h-1(x) = (-3/2)x + 9
Hey User______________
Here is Your Answer...!!!
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LINES AND ANGLES
After observing we get as ..Going horizontal manner we get
1) Alternate Exterior Angles
2) None of these
3) Corresponding Angles
4)Alternate interior Angles
5) Corresponding Angles
Answer:
42.5
Step-by-step explanation:
see attached image.
Answer:
2340
Step-by-step explanation:
fundamental counting principle
