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Alenkasestr [34]
3 years ago
8

PLZZZZ HELP!!!!!!!

Mathematics
1 answer:
grandymaker [24]3 years ago
3 0

Hey User______________

Here is Your Answer...!!!

_____________________

LINES AND ANGLES

After observing we get as ..Going horizontal manner we get

1) Alternate Exterior Angles

2) None of these

3) Corresponding Angles

4)Alternate interior Angles

5) Corresponding Angles

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Find cot θ if csc θ = negative square root of thirty seven divided by six and tan θ > 0.
Ket [755]
You can use the trigonometric identity  1+\cot^2{x}=\csc^2{x}.

1+\cot^2{\theta}=(\frac{-\sqrt{37}}{6} )^2 \\ 1+\cot^2{\theta}=\frac{37}{36} \\ \cot^2{\theta}=\frac{1}{36} \\
\cot{\theta}=\frac{1}{6}

The requirement that \tan{\theta}\ \textgreater \ 0 eliminates -1/6 from being another solution.
6 0
2 years ago
Another question for math. ill give mad points, the question is in attachment
yulyashka [42]
For this case we have the following points:
 y = (- 2, 5)
 z = (1, 3)
 Therefore, the vector yz is given by:
 yz = z - y = (1, 3) - (-2, 5)
 yz = ((1 - (- 2)), (3-5))
 yz = ((1 + 2), -2)
 yz = (3, -2)
 Then, the magnitude is given by:
 lyzl = root ((3) ^ 2 + (-2) ^ 2)
 lyzl = root (9 + 4)
 lyzl = root (13)
 Answer:
 
yz = (3, -2)
 lyzl = root (13)
 option A
5 0
3 years ago
Angel borrowed $141 to buy a stereo. He pays backs $14 each week. How much does he still owes after each week? Use a graph if yo
Harrizon [31]

Logically, he would owe 14 less each week

Let x = # of weeks passed

Algebraic Expression: 141 - 14x =

Week 1: 141 - 14 = 127

Week 2: 141 - 14(2) = 113

Week 3: 141 - 14(3) = 99

etc.....

Hope this helps


3 0
3 years ago
Find five consecutive integers such that: "the sum of the first and 4 times the third is equal to 60 less than 3 times the sum o
Monica [59]

Consecutive integers are integers that come one after another in order. For example, 2, 3, and 4 are all consecutive integers, as well as 100, 101, and 102. In general, if we have some integer n, the consecutive integers following it will be n + 1, n + 2, n + 3, etc. Here, we have five. If we

  • Call the first integer n,
  • Then the second integer will be n + 1,
  • The third will be n + 2,
  • The fourth will be n + 3,
  • And the fifth will be n + 4.

Now, let's break down the equation in English. We'll use #1, #2, #3, #4, and #5 as stand-ins for the five integers just so we can get things set up, then we'll replace them with the expressions we came up with in the first part. Starting from the beginning of the statement, let's translate words to symbols:

  • "The sum of the first and 4 times the third" → #1 + 4 × #3
  • "is equal to" → = (maybe obvious, but still!)
  • "60 less than 3 times the sum of the second, fourth, and fifth" → 3 × (#2 + #4 + #5) - 60

Putting that all together, we get the equation

#1 + 4 × #3 = 3 × (#2 + #4 + #5) - 60.

Replacing our stand-ins for the expressions we came up with, it becomes

n + 4(n + 2) = 3[(n + 1) + (n + 3) + (n + 4)] - 60

We can now start to simplify our equation to find n (the first integer) and the rest will follow easily from that. I'll start by focusing on the left side. We can distribute and combine like terms like so:

n + 4(n+2) = n + 4n + 8 = 5n + 8

Dealing with the right, we can get rid of some redundant parentheses and carry out the same process:

3[(n + 1) + (n + 3) + (n + 4)] - 60 = 3(n + 1 + n + 3 + n + 4) - 60

= 3(3n + 8) - 60 = 9n + 24 - 60 = 9n - 36

Our simplified equation now becomes

5n + 8 = 9n - 36.

Subtracting 5n from either side:

8 = 4n - 36

Adding 36 to either side:

44 = 4n

And dividing either side by 4:

11 = n.

We now know that our first integer is 11, which means that our 5 consecutive integers are 11, 12, 13, 14, and 15.

7 0
3 years ago
Use the graph below for 5 & 6. The graph shows how many bottles a machine fills in a
chubhunter [2.5K]
The constant of proportionality is 600
8 0
3 years ago
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