3 years ago

Graph a line with a slope of 3/4 that contains the point (2,-3).

Mathematics

1 answer:

arsen [322]3 years ago

6 0

Answer:

Step-by-step explanation:

First, plot the point (2, -3) on the graph. Then, use the slope to pick another point. The slope is rise over run. For your slope, the line will go 3 places up and then 4 places to the right. Using a straight-edge, follow the points and you will get the graph of the line.

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Find an equation of the line passing through each of the following pairs of points. a (−3, 1), (0, 3)

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$\bf \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{1}=\stackrel{m}{\cfrac{2}{3}}[x-\stackrel{x_1}{(-3)}]\implies y-1=\cfrac{2}{3}(x+3) \\\\\\ y-1=\cfrac{2}{3}x+2\implies y=\cfrac{2}{3}x+3$