All categories

3 years ago

If I have 5 potatoes weighing a total of 1 kg what would each potato weigh?

2 answers:

4 0

From the information given, we don't know how much each potato weighs. All we know is that when you add up all 5 of them you get one kilogram.
If all five have exactly the same weight then it's 200 grams.

ki77a [65]3 years ago

4 0

Each potato would weigh 200 grams. 1 kg is the equivalent to 1000 grams. So, if you divide 1000 by 5, you get 200 grams. Good luck!

You might be interested in

The line width used for semiconductor manufacturing is assumed to be normally distributed with a mean of 0.5 micrometer and a st

Alinara [238K]

Answer:

There is a 0.82% probability that a line width is greater than 0.62 micrometer.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by

$Z = \frac{X - \mu}{\sigma}$

After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X. The sum of the probabilities is decimal 1. So 1-pvalue is the probability that the value of the measure is larger than X.

In this problem

The line width used for semiconductor manufacturing is assumed to be normally distributed with a mean of 0.5 micrometer and a standard deviation of 0.05 micrometer, so $\mu = 0.5, \sigma = 0.05$ .

What is the probability that a line width is greater than 0.62 micrometer?

That is $P(X > 0.62)$

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{0.62 - 0.5}{0.05}$

$Z = 2.4$

Z = 2.4 has a pvalue of 0.99180.

This means that P(X \leq 0.62) = 0.99180.

We also have that

$P(X \leq 0.62) + P(X > 0.62) = 1$

$P(X > 0.62) = 1 - 0.99180 = 0.0082$

There is a 0.82% probability that a line width is greater than 0.62 micrometer.

3 0

2 years ago

Please Help, and show work..

azamat

Hi there! So the the new price is $93, and went up from $55. Let's subtract the numbers. 93 - 55 is 38. The change is 38. To find the percent markup, we can write and solve a proportion. Set it up like this:

38/55 = x/100

This is because the amount of change goes above the original (55), and x represents the percent out of 100. We are looking for the markup. Let's cross multiply the values. 100 * 38 is 3,800. 55 * x is 55x. 3,800 = 55x. Now, divide each side by 55 to isolate the x. 55x/55 cancels out. 3,800/55 is 69.0909 or 69 when rounded to the nearest whole number. There. The percent of markup is approx. 69%.

3 0

2 years ago

Help me please urgent

marissa [1.9K]

360-150-150=60 arc ac=60, the measure of arc is same as central angle and inscribe angle is half of central angle so answer is 30

5 0

3 years ago

Factor 2x^3+3x^2-23x-12, given that x+4 is a factor

Alex73 [517]

5 0

3 years ago

Read 2 more answers