Answer:
Her usual rate is 0.8333 miles per hour.
Step-by-step explanation:
The velocity formula is given by:
In which d is the distance and t is the time.
She completed the first half of the walk 1 mi/h faster than usual
Her usual rate is v. 1mph faster is v + 1.
The second half of the walk 2 mi/h slower than the first half.
The first half is v + 1.
2mph slower is v + 1 - 2 = v - 1. Then
Total rate:
7.2 hours, and 6 miles. So
One half is v+1 and the other is v - 1. This is why each is multiplied by 0.5.
Her usual rate is 0.8333 miles per hour.
The diffusion time of the red blood cell to take oxygen through the membrane is 25uS.
The small capillaries in the lungs are in close contact and it takes a red blood cell 0.5 seconds to squeeze through the capillary.
The diffusion time for the oxygen across the 1 um thick membrane separating the air is given by,
t = x²/2D
Where,
t is the diffusion time,
x is the thickness of the membrane,
D is the diffusion coefficient.
Putting values,
t = (1 x 10⁻⁹)²/2 x 2 x 10⁻¹¹
t = 10⁻⁷/4
t = 25 x 10⁻⁹ seconds.
t = 25 uS.
so, the diffusion time is 25uS.
To know more about Diffusion, visit,
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B because the square root of 39 is 6.24499799...
Answer:
x=4, MN= 37, LM= 37, y=7.
Step-by-step explanation:
If MP is a perpendicular bisector to LN, then NP and LP are equivalent.
(Solve for y)
2y+2= 16
(Move the +2 to the right side of the equation)
2y= 14
(Divide both sides by 2 to isolate the variable)
y=7
To find x and the measure of MN and LM, solve for x in the following equation:
7x+9 = 11x-7
(Move 7x to the right side of the equation)
9 = 4x-7
(Move -7 to the right side of the equation.)
16= 4x
(Divide both sides by 4 to isolate the variable.)
4= x
Plug x back into both equations to get the measure of MN and ML
MN=7(4)+9
MN= 28+9
MN= 37
LM= 11(4)-7
LM= 44-7
LM= 37
I hope this helps!
