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Paha777 [63]
3 years ago
10

WILL GIVE BRAINLIEST!!!! PLZ HELP ASAP!!!IMAGE BELOW:

Biology
1 answer:
lina2011 [118]3 years ago
4 0

so for the 2nd question: an herbivore that eats only narrow leaves (organism with bb genotypes) will decrease f(b) and increase f(B)

And for the 1st question:

you have to calculate the allele frequencies for each generation and u can do that by writing 2 equations. After u find the values of f(b) and f(B) for each generation by comparing the values you can tell wether or not this population is in equilibrium. If the values have stayed fairly the same that means it’s in equilibrium and it is not evolving. I think this population is not in equilibrium and thus is evolving by looking at the numbers in the table.

If you still have questions or problems with the calculations leave a comment and I’ll help. :))

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Answer:

False

Explanation:

The histones that are more positively charged, tight hardly to negatively charged DNA. So, enzymes, such as acetyltransferases, that reduce the positive charge of histones promote transcription.

Chromatin structure and its modifications can change the package of the DNA and consequently, alter the gene expression. The most common modifications of the chromatin are covalent modifications such as acetylation/deacetylation (by acetyltransferases and eacetylases), methylation (by methyltransferases), and phosphorylation (by kinases).  This is the way of gene expression regulation.

The effects of modifications are different, for example methylation promotes  condensation of the chromatin and as a consequence, prevents binding of transcription factors to the DNA (transcription is repressed).

Acetylation loosens the association between nucleosomes and DNA (because it neutralizes the positive charge of histones) and consequently promotes transcription. Deacetylation is a process opposite to acetylation.

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Answer:

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Explanation:

Hope it helps:)

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