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3 years ago

Please help me do my homework and receive 25 points.

Mathematics

1 answer:

user100 [1]3 years ago

6 0

Fluency
1.) All three
condition: They all have the same size, same angles
2.) The right triangles
condition: They both have the same angles as well as same size
3.)The first and second ones
condition: They both are the same size, and have the same angles
4.) Last 2
condition: Same size, same angles.

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about 10% of the general population are left-handed. If you survey 370 students in a school, about what number can you expect to

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Well, to get the answer, we just divide 370 by 10.
370 divided by 10 = 37
So, the answer is 37
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The measures of the angles of a triangle are shown in the figure below. Solve for x.

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Step-by-step explanation:

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The perimeter Of a rectangle is 30 inches if it’s Lance is three times it’s width find the dimensions.

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A student factors 3x2 – 12 to the following. 3(x2 – 4)

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Answer:

The expression is equivalent , but is not completely factored

Step-by-step explanation:

A student factors 3x² – 12 to the following. 3(x² – 4)

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If we multiply by 3 by opening the brackets then we get the same expression 3x² – 12.

However; 3(x² – 4), could be factored further;

To get; 3(x + 2)(x - 2) ; since x² – 4 is a difference of two squares;

Therefore;

3x² – 12 = 3(x² – 4) = 3(x + 2)(x - 2)

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A new process of more accurately detecting anaerobic respiration in cells is being tested. The new process is important due to i

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Answer:

a) 0.97605 = 97.605% probability that the process will signal.

b) 0.2076 = 20.76% probability that microaerophiles are present.

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

In which

P(B|A) is the probability of event B happening, given that A happened.

$P(A \cap B)$ is the probability of both A and B happening.

P(A) is the probability of A happening.

a. What is the probability that the process will signal?

It signals in these following moments:

97.8% of 31%(contains obligate anaerobes).

98.1% of 27%(contains facultative anaerobes).

96.5% of 21%(contains microaerophiles).

99.2% of 12%(contains nanaerobes).

95.9% of 9%(contains aerotolerant). So

$p = 0.978*0.31 + 0.981*0.27 + 0.965*0.21 + 0.992*0.12 + 0.959*0.09 = 0.97605$

0.97605 = 97.605% probability that the process will signal.

b. If the test signals, what is the probability thatmicroaerophiles are present?

Event A: Test signals

Event B: Contains microaerophiles

0.97605 = 97.605% probability that the process will signal.

This means that $P(A) = 0.97605$

Intersection of events A and B:

Signals containing microaerophiles, which is 96.5% of 21%. So

$P(A \cap B) = 0.965*0.21 = 0.20265$

The probability that microaerophiles are present is:

$P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.20265}{0.97605} = 0.2076$

0.2076 = 20.76% probability that microaerophiles are present.

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3 years ago