Answer:
{3, 4, 5, 6, 7, 8, 9, 10, 11}
Step-by-step explanation:
Let integer be x
x > 2 and x < 12
gives
2 < x < 12
All such integers are {3, 4, 5, 6, 7, 8, 9, 10, 11}
Answer it takes away 2 than adds 3 and takes away 2 than instead of adding 3 on the fourth number it adds 6 so maybe it doubles the number it adds every time or it adds three onto the last number it added with and continues like that.
Step-by-step explanation:
Part A. Your model is as good as any. It is hard to tell if the label needs to include the descriptor (length = 12 ft, for example). Certainly your model is sufficient for Part B.
Part B. The total area is the sum of the areas of each of the 6 faces of the box. Opposite faces are the same area, so you have
A = 2(LW +WD +LD) = 2(LW +D(L +W))
Subsituting the given dimensions, you get
A = 2((12 ft)(6 ft) +(3 ft)(12 ft +6 ft))
A = 2(72 ft² +(3 ft)(18 ft))
A = 2(72 ft² +54 ft²) = 252 ft²
The least amount of paper required to cover the box is 252 ft².
midpoint of AB (M)=(1,4)=(x,y)
COOrdinates of A=(-3,-6)=(X1,Y1)
coordinates of B=?
using midpoint formula,
X=(X1+X2/2)
or,1=(-3+X2/2)
or,2=-3+X2
or,2+3=X2
5=X2
<h2> And</h2>
Y=(Y1+Y2/2)
or,4=(-6+Y2/2)
or,4×2=-6+Y2
or,8+6=Y2
14=Y2
so,co-ordinates of B are(5,14).
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5/6 hour = 5/6 × 60 = 300/6 = 50 minutes
8 tasks in 50 minutes
1 task = 50/8 = 6 1/4 minutes
a. robot completes task in 6 1/4 minutes
b. #tasks per hour =
#of tasks × time takes to do task < or = 60
n × 6.25 = 60
6.25n = 60.
n= 60/6.25 = 9.6
robot can complete 9 tasks in one hour