Let's say you want to compute the probability
where
converges in distribution to
, and
follows a normal distribution. The normal approximation (without the continuity correction) basically involves choosing
such that its mean and variance are the same as those for
.
Example: If
is binomially distributed with
and
, then
has mean
and variance
. So you can approximate a probability in terms of
with a probability in terms of
:
where
follows the standard normal distribution.
Y=1/3x + 2 as the y intercept is 2 and slope is 1/3
<span>The equation that shows the cost of a mix of Arabica and Robusta beans is: 700 A + 1,200 R = 1,000,000. We know that a mixture contains 1,000 pounds of Arabica beans ( A = 1,000 ). So: 700 * 1,000 + 1,200 R= 1,000,000; 700,000 + 1,200 R = 1,000,000 ; 1,200 R = 1,000,000 - 700,000 ; 1,200 R = 300,000 ; R = 300,000 : 1,200 ; R = 250. Answer: There should be: R = 250 pounds.</span>
Either a pecan or walnut means you add the probabilities together
20% plus 35% equals 55%
Answer:
11/14
Step-by-step explanation:
11/4 / 3 1/2
3 1/2= 3*2+1= 6+1=7/2
11/4 * 2/7= 22/28
22/2=11
28/2= 14
11/14
