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Vanyuwa [196]
3 years ago
6

What value of x is in the solution set of 2(3x - 1) = 4x - 6?

Mathematics
1 answer:
Aliun [14]3 years ago
8 0

Answer:

x=-2

Step-by-step explanation:

2(3x - 1) = 6x - 2 = 4x - 6 \\ 2x =  - 4  \\ x =  - 2

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7 0
3 years ago
Inequalities Exam
Igoryamba

Answer:

t > 8

Step-by-step explanation:

Given that :

Initial volume = 16 litres

Addition rate = 4 litres per minute

Target volume > 48 litres

Let number of minute for which water is added to achieve these = t

Mathematically,

Initial volume + (addition rate * t) > target volume

16 + 4t > 48

Collect like terms

4t > 48 - 16

4t > 32

Divide both sides by 4

4t/4 > 32/4

t > 8

Laura will need add water at 4 Litre per minute rate for more than 8 minutes

3 0
3 years ago
A 2.25 units<br> C 5 units<br> B 4 units<br> 0 16 units
S_A_V [24]

Answer:

B

Step-by-step explanation:

If 2 chords of a circle intersect, then the product of the parts of one chord is equal to the product of the parts of the other chord , that is

BW × WD = AW × WC ( substitute values )

6 BW = 3 × 8 = 24 ( divide both sides by 6 )

BW = 4 units

5 0
3 years ago
Read 2 more answers
s (as needed, enter in your answers as inf): for the solution through the top-left point: for the solution through the origin: f
antoniya [11.8K]
  1. 3(y->3) is the direction of the top left point's solution.
  2. The answer via origin is often 3(y->3).
  3. The bottom-right point of the solution tends to -infinity.

As x rises, all converge on 3, which is stable.

As x rises, all shift away from -1, making it unstable.

What are equilibrium solutions?

⇒ It is the response to which other responses either move in the opposite direction or tend to approach when t. Because the solution does not depend on time (or any other variable you are integrating over) at those moments, the situation is in equilibrium. Stable solutions are those that "attract" other solutions that started nearby. Stable solutions are those that don't "push away" unstable ones that started nearby. Finally, solutions that, depending on the side from which other solutions started, either attract or push other solutions are referred to as semi-stable solutions. The values of y for which the differential equation states that dy/dt=0 are the equilibrium solutions. Therefore, at those values of y, there are constant solutions.

Calculation:

The equilibrium solutions:

0.7(1+y) (3−y)=0

⇒ y=-1 and y=3 are the equilibrium solutions.

Hence y=-1 and y=3 are the equilibrium solutions.

Learn more about equilibrium solutions here:

brainly.com/question/23885178

#SPJ4

3 0
2 years ago
How to find are if a sector
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Use the formula 1/2 radius^2 theta
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