Answer:
Step-by-step explanation:
cotx/cscx=cosx
Start on the left side.
cos(x) csc(x)
Apply the reciprocal identity to csc (x) .
cos(x) 1/sin(x)
Simplify
cos(x) 1/sin(x)cos(x)/sin(x)
Rewrite cos(x)/sin(x) as cot(x) .
cot(x)
Because the two sides have been shown to be equivalent, the equation is an identity.
cos(x) csc(x)=cot(x) is an identity
cot(x)−tan(x)/sin(x)cos(x)=csc^2(x)−sec^2(x) is an identity
You are correct :)
any combination would work out. the most common is x and y. or you may use f(x) and x.
Domain is all real, yep
vertex of y values is from2 to infinity, so 2nd is false
y int is where x=0, that is at y=2, nope so 3rd is false
2 up and 1 to left, so no for 4th
x intercept? there are none
answer is only first option
Answer:
A
Step-by-step explanation:
Just by looking at the graph you can eliminate some silly answers such as D and B, everything besides the slope is obvious at least:
The y int is -2
The line is negative
The standard parent function equation is just y = x with a slope of 1.
This graph is clearly a bit steeper than the normal parent function, so it has a slope that is great than -1, not less . So the only answer left is A
If you want to be sure, you can calculate the slope using rise over run and the slope should be somewhat close to -1.5 which is equal to -3/2
Thanks me later :)