The function is:
f ( x ) = 2 / ( x² + 3 x - 10 )
x² + 3 x - 10 = x² + 5 x - 2 x - 10 = x ( x + 5 ) - 2 ( x + 5 ) =
= ( x + 5 ) ( x - 2 )
x + 5 = 0 => x = - 5
x - 2 = 0 => x = 2
Answer:
The vertical asymptotes are: x = - 5 and x = 2.
False
X is the output, and y is the input
Answer: ten thousand and 3
Step-by-step explanation:
Y = 3x + 3
y = x - 1
As you can see, both equations are set to equal y. This means the right sides of each equation are equal, since y is isolated in both equations. So to solve this particular system of equations for x, set the right sides of both equations equal to each other. After you've done that, you can proceed to solve the equation algebraically for the variable, x.
3x + 3 = x - 1
2x + 3 = -1
2x = -4
x = -2
Negative two is the x-value. To find the y-value, substitute -2 for x into either equation and solve algebraically for y.
y = x - 1
y = -2 - 1
y = -3
The final step is to check all work by plugging both x- and y-values back into both equations.
y = 3x + 3
-3 = 3(-2) + 3
-3 = -6 + 3
-3 = -3 -- This is true
y = x - 1
-3 = -2 - 1
-3 = -3 -- This is true.
Answer:
(-2, -3)
Answer:
1. sin and cos 2. complementary 3. sinA = cosB 4. 80° 5. 17
Step-by-step explanation:
1. cofunctions: having the same value at complementary angles
sin θ = cos (90 - θ), <em>or </em>cos θ = sin(90 - θ)
2. complementary: two angles sum to 90°, supplementary: two angles sum to 180°
one of the angle in a right triangle must be a right angle = 90°
180°<em>(sum of angles of a triangle) - </em>90° = 90°<em>(the sum of the other two angles)</em> => which is complementary
3. sinA = cosB
4. cos θ = sin(90 - θ)
=> cos 10° = sin(90 - 10°)
=> cos 10° = sin(80°)
5. sin θ = cos (90 - θ)
=> sin 73° = cos (90 - 73°)
=> sin 73° = cos (17°)
