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Valentin [98]
3 years ago
6

Who to tell if the question is rational or irrational

Mathematics
1 answer:
Flauer [41]3 years ago
8 0

An irrational number can be written as a decimal, but not as a fraction. An irrational number has endless non-repeating digits to the right of the decimal point. Any number that can be written as a fraction or a ratio is a rational number. The product of any two rational numbers is therefore a rational number, because it too may be expressed as a fraction.
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Fill in the missing reason for the proof.
8_murik_8 [283]
The answer is c. they are indeed vertical angles
4 0
3 years ago
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5/9 power -2 * 3/5 power -3 * 3/5 power 0
zavuch27 [327]

Answer:

15

Step-by-step explanation:

5/9^-2 = 81/25

3/5^-3 = 125/27

3/5^0 = 1

81/25 x 512/27 x 1 = 15

3 0
1 year ago
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Is 3/5 + 3/5 negative or positive <br> ​<br> ​<br> ​
Elan Coil [88]

Answer:

positive

Step-by-step explanation:

when there is no sign in front of the numbers, we can assume that the numbers are positive

8 0
2 years ago
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Suppose that the position of one particle at time is given by x1=3sin t, y1 = 2 cos t, 0 ≤ t ≤ 2π and the position of a second p
Mashcka [7]

Answer:

there is no collision between the particles

Step-by-step explanation:

for the first particle

x1=3sin t, y1 = 2 cos t, 0 ≤ t ≤ 2π

for the second particle

x2 = -3 + cos t, y2 = 1 + sin t, 0 ≤ t ≤ 2π

then for the collision

x1=x2 → 3*sin t = -3 + cos t → sin t= -1 + (cos t)/3→ 1+ sin t = (1/3)cos t  

y1=y2 → 1 + sin t = 2 cos t → (1/3)cos t  = 2 cos t →(1/3) = 2

since 1/3 ≠ 2 there is no collision between the particles

6 0
3 years ago
(f/g)(x)and (f/g)(7)
Phoenix [80]

Answer:

(\frac{f}{g})(x)=\frac{f(x)}{g(x)}\\\\(\frac{f}{g})(7)=\frac{f(7)}{g(7)}

Step-by-step explanation:

Division operation of function:If\ f(x)\ and\ g(x)\ are\ two\ functions\ then\ (\frac{f}{g})(x)=\frac{f(x)}{g(x)}

Here\ we\ have\ to\ find\ (\frac{f}{g})(7)\\\\(\frac{f}{g})(7)=\frac{f(7)}{g(7)}

Example:

Take\ f(x)=3x^2+1,\ g(x)=x+1\\\\(\frac{f}{g})(x)=\frac{f(x)}{g(x)}\\\\(\frac{f}{g})(x)=\frac{3x^2+1}{x+1}\\\\f(7)=3\times 7^2+1\\\\f(7)=3\times 49+1\\\\f(7)=148\\\\g(7)=7+1\\\\g(7)=8\\\\(\frac{f}{g})(7)=\frac{f(7)}{g(7)}\\\\(\frac{f}{g})(x)=\frac{148}{8}

7 0
3 years ago
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