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irina1246 [14]
3 years ago
14

This is very very simple

Mathematics
2 answers:
Advocard [28]3 years ago
8 0

Answer:

2

Step-by-step explanation:

2+2+4=8/4=2

Xelga [282]3 years ago
3 0

Answer:

2!

Step-by-step explanation:

You might be interested in
How to do this ?<br> Don’t understand it
riadik2000 [5.3K]
X=y+3
<span>-5x-4y=<span>30
-------------------
Substitute y + 3 for x in </span></span>-5x-4y=30
<span><span>-5<span>(y+3)-</span></span>4y</span>=<span>30
</span>-9y-15=<span>30
</span>----------------------------
Add 15 to each side
<span><span>-9y-15</span>+15</span>=<span>30+<span>15
-9y = 45
</span></span>-----------------------------------
Divide each side by -9
-9y ÷ -9 = 45 ÷ -9
y = -5
Now we solve for x
====================================================================
Substitute -5 for y in x = y + 3
x=-<span><span>5</span>+<span>3
</span></span>x = -2
----------------------
(-2,-5) is your answer


7 0
3 years ago
Help me pls thank you alot!
damaskus [11]
Your answer will be -1/7
4 0
2 years ago
Read 2 more answers
2. John earns a 3% commission for every car he sells. Today he sold a car for $13,600. How much commission did he receive? (To f
OlgaM077 [116]

Answer:

$408

Step-by-step explanation:

Find 3% of $13,600:

3 * 13,600 / 100 = $408

7 0
3 years ago
Y = 6x - 4<br> y = -x + 3
likoan [24]

Answer:

  (1, 2)

Step-by-step explanation:

Subtract the second equation from the first:

  (y) -(y) = (6x -4) -(-x +3)

  0 = 7x -7 . . . . .  simplify

  0 = x - 1 . . . . . . divide by 7

  1 = x . . . . . . . . . add 1

  y = -1 +3 = 2 . . . substitute into the second equation

The solution is (x, y) = (1, 2).

4 0
3 years ago
What is the solution set of x2 + 5x + 1 = 0?
DerKrebs [107]

Answer:

\huge\boxed{\left\{-\dfrac{5+\sqrt{21}}{2};\ \dfrac{-5+\sqrt{21}}{2}\right\}}

Step-by-step explanation:

x^2+5x+1=0\\\\\text{Use the quadratic formula:}\\\\\text{For}\ ax^2+bx+c=0\\\\\Delta=b^2-4ac\\\\\text{if}\ \Delta < 0,\ \text{then the equation has no real solution}\\\text{if}\ \Delta=0,\ \text{then the equation has one real solution}\ x=\dfrac{-b}{2a}\\\text{if}\ \Delta>0,\ \text{then the equation has two real solution}\ x=\dfrac{-b\pm\sqrt{\Delta}}{2a}

\text{We have}\\\\a=1,\ b=5,\ c=1\\\\\Delta=5^2-4(1)(1)=25-4=21>0\\\\x=\dfrac{-5\pm\sqrt{21}}{2(1)}=\dfrac{-5\pm\sqrt{21}}{2}

3 0
3 years ago
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