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Stells [14]
3 years ago
13

(5x+38)=(8x-19) what is the answer?

Mathematics
2 answers:
Juliette [100K]3 years ago
8 0

Answer:

x=19

Step-by-step explanation:

To solve this, we need to get x by itself

5x+38=8x-19

First, we need to move all the numbers to the same side, and all the variables to the other side

Let’s add 19 to both sides

5x+38+19=8x-19+19

5x+57=8x

Now, subtract 5x from both sides

5x-5x+57=8x-5x

57=3x

Now all the numbers are on one side, and the variables are on the other. x is still now by itself, it is being multiplied by 3. To undo this, divide both sides by 3.

57/3=3x/3

19=x

timofeeve [1]3 years ago
3 0

Answer:

Step-by-step explanation:

5x + 38 = 8x - 19

by transposing method,

5x - 8x = -19-38

-3x = -57

3x = 57

x = 57/3

x = 19

hope this helps

plz mark it as brainliest

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4 years ago
The half-life of Radium-226 is 1590 years. If a sample contains 400 mg, how many mg will remain after 2000 years?
Assoli18 [71]

Answer:

167.27 mg.

Step-by-step explanation:

We have been given that the half-life of Radium-226 is 1590 years and a sample contains 400 mg.

We will use half life formula to solve our given problem.

N(t)=N_0*(\frac{1}{2})^{\frac{t}{t/2}, where N(t)= Final amount after t years, N_0= Original amount, t/2= half life in years.

Now let us substitute our given values in half-life formula.

N(2000)=400*(\frac{1}{2})^{\frac{2000}{1590}

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3 years ago
What expression is equivalent to
kaheart [24]

Answer:

Option (2)

Step-by-step explanation:

Given expression is \sqrt[3]{64a^6b^7c^9}

By simplifying this expression,

\sqrt[3]{64a^6b^7c^9}=\sqrt[3]{(4)^3(a^2)^3(b^2)^3(b)(c^3)^3}

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Option (1)

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Option (2)

4a^2b^2c^3(\sqrt[3]{b}) [Fully simplified form]

Option (3)

8a^3b^3c^4(\sqrt[3]{bc} ) [Fully simplified form]

Option (4)

8a^2b^2c^3(\sqrt[3]{b})

Expression given in Option (2) is equivalent to the given expression.

Option (2) will be the answer.

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s344n2d4d5 [400]

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Step-by-step explanation:

8 0
3 years ago
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