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lina2011 [118]
4 years ago
14

(7.RP.3) When invested at an annual interest rate of 6% an account earned $180.00 of simple interest in one year. How much money

was originally invested in account? (1 pt) * a) $10.80 b) $108 c) $648 d) $30 e) $300 f) $3,000
Mathematics
1 answer:
tresset_1 [31]4 years ago
4 0

Answer:  f) $3,000


Step-by-step explanation:

Given: Simple interest amount S.I.= $180.00

The rate of interest annually= 6%

In decimal , the rate of interest annually r = 0.06

Time period t = 1 year

Let 'P' be the principal amount invested in account.

The formula to calculate simple interest is as :-

\text{Simple interest }=Prt

\\\Rightarrow180=P(0.06)\times1\\\\\Rightarrow\ P=\frac{180}{0.06}\\\\\Rightarrow\ P=\$3000

Hence, the principal amount invested in account = $3000

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ryzh [129]

-x - 7y = 18

4x + 7y = -30

The -7y and 7y cancel by addition.

Thus, 3x = -12

Divide both sides by 3

x = -4

Plug in -4 for x

Thus, -(-4) - 7y = 18

4 - 7y = 18

Subtract 4 to both sides; 4 - 4 - 7y = 18 - 4

Simplify, -7y = 14

Divide both sides by -7; -7y/-7 = 14 / -7

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4 years ago
write a word problem that you can represent with the expression 8÷2/3. draw a model and use equation to show the solution​
Mariana [72]

Answer:

The word problem is " In a class there are 8 boys and these are 2/3rd parts of total students. How many students are there".

Step-by-step explanation:

The given expression is

8\div \frac{2}{3}

We need write a word problem which is solved by the above expression.

Word problem : In a class there are 8 boys and these are 2/3rd parts of total students. How many students are there.

Solution:

Let the total number student be x.

x\times \frac{2}{3}=8

Divide both sides by 2/3.

x=\dfrac{8}{\frac{2}{3}}

x=\dfrac{8\times 3}{2}

x=12

Therefore, the total number of students is 12.

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