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stiks02 [169]
3 years ago
6

AB←→ is reflected to form ​​ ​ A'B'←→− ​.

Mathematics
2 answers:
tia_tia [17]3 years ago
6 0
The correct answer for this problem is C.) reflection across y=x .
Levart [38]3 years ago
5 0

Answer:

reflection across y = x.

Step-by-step explanation:

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What is the circumference of circle with a diameter of 9 feet? Use 3.14 for tt
ankoles [38]

Answer:

28.26

Step-by-step explanation:

The formula for calculating diameter is π<em>d</em> (pi times the diameter), so 3.14 times 9 is 28.26.

4 0
3 years ago
Read 2 more answers
F= 8/5 (c) + 40 when c=5
Molodets [167]

Answer:

F = 48

Step-by-step explanation:

F= 8/5 (c) + 40

Let c=5

F = 8/5 * 5 +40

  = 8 + 40

  = 48

6 0
3 years ago
Read 2 more answers
Jane took 15 min to drive her boat upstream to​ water-ski at her favorite spot. Coming back later in the​ day, at the same boat​
s344n2d4d5 [400]

Answer:

The speed of the boat in still water = 8 Km/hr

Step-by-step explanation:

Let the speed of the boat be x

According to question

(x-4)15 = (x+4)5

3x-12 = x+4

⇒x = 8 km/hr

7 0
2 years ago
Casey said that 0.03*1,000 is 3 explain why caseys answer is wrong what mistake do u think he made
Igoryamba
<span>0.03 x 1,000=30! In multiplying decimals, you'll move the decimal's period to the number of zeroes in the multiplier! 1,000 has 3 zeroes. So, it's equal to 30. So basically he was wrong because 0.03 times 1,000 doesn't equal 3 it equals 30. He made the mistake of not moving the decimal point enough.</span>
6 0
3 years ago
A company claims that the mean weight per apple they ship is 120 grams with a standard deviation of 12 grams. Data generated fro
Veronika [31]

Answer:

There is no sufficient evidence to reject the company's claim at the significance level of 0.05

Step-by-step explanation:

Let \mu be the true mean weight per apple the company ship.  We want to test the next hypothesis

H_{0}:\mu=120 vs H_{1}:\mu\neq 120 (two-tailed test).

Because we have a large sample of size n = 49 apples randomly selected from a shipment, the test statistic is given by

Z=\frac{\bar{X}-120}{\sigma/\sqrt{n}} which is normally distributed. The observed value is  

z_{0}=\frac{122.5-120}{12/\sqrt{49}}=1.4583. The rejection region for \alpha = 0.05 is given by RR = {z| z < -1.96 or z > 1.96} where the area below -1.96 and under the standard normal density is 0.025; and the area above 1.96 and under the standard normal density is 0.025 as well. Because the observed value 1.4583 does not fall inside the rejection region RR, we fail to reject the null hypothesis.

5 0
3 years ago
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