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tino4ka555 [31]
4 years ago
10

Divide. Show your work. (6x^4-5x^3+6x^2)/2x^2

Mathematics
1 answer:
serg [7]4 years ago
6 0
We can do like we did before, distribute the denominator,

\bf \cfrac{6x^4-5x^3+6x^2}{2x^2}\implies \cfrac{6x^4}{2x^2}-\cfrac{5x^3}{2x^2}+\cfrac{6x^2}{2x^2}\implies \cfrac{6}{2}\cdot \cfrac{x^4}{x^2}-\cfrac{5}{2}\cdot \cfrac{x^3}{x^2}+\cfrac{6}{2}\cdot \cfrac{x^2}{x^2}
\\\\\\
3 x^4x^{-2}-\cfrac{5}{2}x^3x^{-2}+3x^2x^{-2}\implies 3x^{4-2}-\cfrac{5}{2}x^{3-2}+3x^{2-2}
\\\\\\
3x^2-\cfrac{5}{2}x+3x^0\implies 3x^2-\cfrac{5}{2}x+3
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Answer:

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Step-by-step explanation:

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Answer:

<h3>\boxed{ \bold{ \boxed{ \sf{ - 13}}}}</h3>

Step-by-step explanation:

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let's find :

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