Answer:
For the first one, R would be = -3/5
In the decimal form that would be -0.6
For the second one, K = 2/19
In the decimal form, it would be 0.10526315
…
Step-by-step explanation:
Answer:
discount=MP-SP
=Rs420-Rs405
=Rs15
Step-by-step explanation:
Answer:
Mean and Variance of the number of defective bulbs are 0.5 and 0.475 respectively.
Step-by-step explanation:
Consider the provided information,
Let X is the number of defective bulbs.
Ten light bulbs are randomly selected.
The likelihood that a light bulb is defective is 5%.
Therefore sample size is = n = 10
Probability of a defective bulb = p = 0.05.
Therefore, q = 1 - p = 1 - 0.05 = 0.95
Mean of binomial random variable: 
Therefore, 
Variance of binomial random variable: 
Therefore, 
Mean and Variance of the number of defective bulbs are 0.5 and 0.475 respectively.
Answer:
m = 2
Step-by-step explanation:
m m+3
----- = ----------
4 10
Using cross products
10m = 4(m+3)
Distribute
10m = 4m+12
Subtract 4m from each side
10m-4m = 4m-4m+12
6m = 12
Divide by 6
6m/6 = 12/6
m = 2