x^2 + y^2 + 2x - 6y + 1 = 0
x^2 +2x + 1 + y^2 - 6y = 0
x^2 + 2( x × 1) + 1^2 + y^2 - 2(y×3) + 3^2 -3^2 =0
(x+1)^2 + (y-3)^2 = 3^2
comparing with circle equation
(x-a)^2 + (y - b)^2 = r^2
where (a , b) is centre of circle.
so we get center of circle is
(-1, 3)
x/6+4= 15
Subtract 4 from both sides; 4s cancel each other out
x/6+4-4= 15-4
x/6= 11
multiply both sides by 6 to eliminate fraction (multiply by reciprocal of 1/6)
(x/6)(6)= (11)(6)
x= 66
ANSWER: x= 66
Hope this helps! :)
a) The point-slope form of the equation of a line through point (h, k) with slope m is
y - k = m(x - h)
In point-slope form, the equation of the line through (-3, -7) with slope -6/5 is
y + 7 = (-6/5)(x + 3)b) The graph of
y = |x|-4
represents a
translation downward 4 units of the graph of
y = |x|
It
retains the same general shape and axis of symmetry, but will have two (2) x-intercepts instead of one (1).
Answer:
vdv
Step-by-step explanation:
vfvfvdv