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____ [38]
3 years ago
5

Last week at the park Haeather ran 4 miles in 48 minutes when she runs her next race she Hope's to improve her time by 2 minutes

per mile
Last week at the park what was haeather rate of speed in miles per hour ​
Mathematics
1 answer:
Korvikt [17]3 years ago
3 0

Answer:

Haeather ran at a speed of 5 miles per hour.

Step-by-step explanation:

Given that last week at the park Haeather ran 4 miles in 48 minutes, to determine what was Haeather rate of speed in miles per hour the following mathematical calculation must be performed:

48/4 = 12

Thus, Haeather ran 1 mile every 12 minutes.

60/12 = 5

1 x 5 = 5

Therefore, Haeather ran at a speed of 5 miles per hour.

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Newton's Law of Cooling states that the rate of change of the temperature of an object, T, is proportional to the difference of
maria [59]

Answer:

  305 °F

Step-by-step explanation:

The core temperature of the object after 4 hours can be found using an exponential decay formula to model the decay of the difference between core temperature and ambient.

<h3>Cooling Model</h3>

The solution to the differential equation described by Newton's law of cooling is the exponential equation ...

  y = ab^t +c

where 'a' is the initial core temperature difference from ambient, 'b' is the decay factor of that difference in 1 unit of time period t. 'c' is the ambient temperature.

For this problem, the ambient temperature is c=80, and the differences of interest are ...

  a = 1200 -80 = 1120

  b = (830 -80)/1120 = 75/112

Using these values in the model gives ...

  y = 1120(75/112)^t +80 . . . . . . where y(t) is the core temperature at time t

Note that units of time are hours.

<h3>Application</h3>

We want y when t=4.

  y = 1120(75/112)^4 +80 ≈ 1120(0.20108) +80 ≈ 305.212

The core temperature after 4 hours is about 305 °F.

__

<em>Additional comment</em>

The differential equation will have a solution of the form ...

  T-T_R=(T_0-T_R)e^{kt}

where k = ln(75/112) ≈ -0.40101

In the above, we defined b = e^k = 75/112. Accuracy with this fraction can be better than using a truncated value of k.

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