Answer:
1, Breaks at 267m 534m, 801m, 1068m, 1335m, 1,602m. = 6 equal breaks. So his first break is 267, as this shows equal breaks for the first journey as asked in question.
2. 9,345m = 5 journeys with 4 pieces of wood. =934500cm
Double for return is more likely answer Return is = 18,690m = 1869000cm as they asked for cm and was total distance as asked in question to deliver 20 pieces of wood.
Step-by-step explanation:
This is easy instead of dividing by 6 we divide by 7
This is because the 6th break would not be at the start or at the end.
An example is with number 10 and 4 breaks
2,4,6,8 are the breaks if number was 10.
But if 10 asked for 5 breaks it would go decimal and divide by 6 which is one more than 5.
So the answer to 1) is 1869/7 = 267m, (+267) 534m, (+267), 801m, (+267)1068m, (+267)1335m (+267) 1602 metres.
Here he still walks for another 267 minutes and finishes meaning he had 6 equal breaks before hand, before he finishes the journey with the wheelbarrow.
Answer 2) We divide 20/4 = 5 then multiply 1869 x 5 to equal the 4 pieces of wood x 5 times. We find 1869 x 5 = 9345
Note you would have to show long division ie) 9 x 5 under each other as long division workings, note is the only product that you do not 'add a zero to' as its tens, so that when you multiply out 5 x 6 = 5x 6 as a zero is added to make 5 x 60 below that you get answer 300 and 9 x 5 is above is showing 45 and continue with the hundred and thousand product underneath until you get to 9345.
Then as it is a return journey we take 9,345 x 2 and say return journey = 18,690m
