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Sauron [17]
3 years ago
10

Mark mowed 3 lawns in 1 hour how many lanws could he mow in 4 hour​

Mathematics
2 answers:
Radda [10]3 years ago
8 0

Answer:

3/1 = x/4

x = 12 lawns he can mow in 4 hours

Step-by-step explanation:

Bond [772]3 years ago
6 0
He can mow 12 lawns in 4 hours.
to get the answer you just multiply the amounts of lawns he mowed by the hours it’s asking.
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What should be subtracted from -8xy + 2x^2 + 3y^2 to get x^2 + 2
Minchanka [31]

Answer:

x^2 - 8xy + 3y^2 - 2

Step-by-step explanation:

(-8xy + 2x^2 + 3y^2) - unknown = x^2 + 2

- unknown = x^2 + 2 + 8xy - 2x^2 - 3y^2

- unknown = -x^2 + 8xy - 3y^2 + 2

Unknown = x^2 - 8xy + 3y^2 - 2

Check:

(-8xy + 2x^2 + 3y^2) - (x^2 - 8xy + 3y^2 - 2)

= -8xy + 2x^2 + 3y^2 - x^2 + 8xy - 3y^2 + 2

= -8xy + 8xy + 2x^2 - x^2 + 3y^2 - 3y^2 + 2

= x^2 + 2

8 0
3 years ago
What is the simplified expression for 6(2(y+x))?
koban [17]
It should be B I know how to do it
5 0
3 years ago
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In AVWX, XV<br> W X and mW<br> - 27°. Find m_X.
SashulF [63]

Answer:

m<X = 126^{o}

Step-by-step explanation:

From the given isosceles triangle, we have;

<W and <V as the base angles

So that,

m<W = m<V = 27 (base angles of an isosceles triangle are equal)

Thus,

m<X + m<V + m<W = 180 (sum of angles in a triangle)

m<X + 27 + 27 = 180

m<X + 54 = 180

m<X = 180 - 54

       = 126

m<X = 126^{o}

8 0
3 years ago
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Which expression is equivalent to log_5(x/4)^2?
viktelen [127]

For this case we must find an expression equivalent to:

log_ {5} (\frac {x} {4}) ^ 2

So:

We expanded log_ {5} ((\frac {x} {4}) ^ 2)by moving 2 out of the logarithm:

2log_ {5} (\frac {x} {4})

By definition of logarithm properties we have to:

The logarithm of a product is equal to the sum of the logarithms of each factor:

log (xy) = log (x) + log (y)

The logarithm of a division is equal to the difference of logarithms of the numerator and denominator.

log (\frac {x} {y}) = log (x) -log (y)

Then, rewriting the expression:

2 (log_ {5} (x) -log_ {5} (4))

We apply distributive property:

2log_ {5} (x) -2log_ {5} (4)

Answer:

An equivalent expression is:

2log_ {5} (x) -2log_ {5} (4)

3 0
3 years ago
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