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pychu [463]
3 years ago
9

Write the equation of the line that passes through (-2,-9) and (6,1)

Mathematics
1 answer:
BlackZzzverrR [31]3 years ago
6 0

Answer: y= 5/4x+b

Step-by-step explanation:

Label your coordinates x1,y1 and x2,y2 then do the equation y2-y1 divided by x2-x1

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Does anyone know how to solve this?
erik [133]

Answer:

A point in polar coordinates is written as (R, θ)

If we want to transform this point to rectangular coordinates, we get:

x = R*cos(θ)

y = R*sin(θ)

Now we can remember that the sine and cosine functions have a period of 2*pi, then:

cos(θ) = cos(θ + 2*pi)

or:

cos(θ) = cos(θ + 2*pi + 2*pi)

and so on.

Then the point (R, θ) is the same as (R, θ + 2*pi) and (R, θ + k*(2*pi))

where k can be any integer number.

Then if we have a point in polar coordinates:

(-4, -5*π/3)

Then another two polar representations of this point are:

(-4, -5*π/3 + 2*π) = (-4, -5*π/3 + 6*π/3) = (-4, π/3)

Now we can not add 2*π (nor subtract) because we would have an angle outside the range [-2*π, 2*π]

For example, if we have:

(-4, π/3 + 2*π) = (-4, 7*π/3)

And we can not change the value of the radius and get the coordinates for the same point.

So another representation could be something like:

(-8/2, π/3)

Where i just wrote -4 in another way.

Now, a really important point.

When working with polar coordinates, we always use R as a positive number (here you can see that R is negative) so this is not the standard notation for the polar representation of a point.

8 0
3 years ago
Geometry Question Please Answer Quick!
kicyunya [14]

The area is (BK) times (AK or CK).

If you have no numbers given, it's not possible to find the length of BK, or the actual number that represents the area.


6 0
3 years ago
What is 5 less than product of 6 and s? A.6s-5 <br> B.5-6s<br> C.5+6-s<br> D.6-s-5
JulijaS [17]
5-6s
5 - 6s
8 0
3 years ago
Evaluate 3a+15+bc−6, when a=7, b=3, and c=15.<br><br> Enter your answer in the box.
melamori03 [73]
I think it's 75.
____________
5 0
3 years ago
Read 2 more answers
Find the 14th term of the geometric sequence 3,6,12,24.
jekas [21]
An=a1(r)^(n-1)
a1=first term
r=common rati

common ratio is a term divded by previous term
6/3=2
r=2

first term is 3

an=3(2)^(n-1)
14th term
a14=3(2)^(14-1)
a14=3(2)^13
a14=3(8192)
a14=24576

the 14th term is 24576


5 0
3 years ago
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