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2 years ago

Y=4x+8x, Solve for x. It's x=y/12, I just need to know how to work it out.

Mathematics

1 answer:

Scrat [10]2 years ago

4 0

Step-by-step explanation:

<h2>Answer:-</h2>

$\tt{y = 4x+8x}$

First, we need to add up the x.

We know that 4+8 = 12, so

$\tt{4x+8x=12x}$

Now, equating it to y,

$\tt{y = 12x}$

Now, if I multiply $\tt{\dfrac{1}{12}}$ on both sides,

I get,

$\tt{\dfrac{y}{12}= \dfrac{\cancel{12}x}{\cancel{12}}}$

Now, as 12 got cancelled , I got the final answer as

$\boxed{\tt{x =\dfrac{y}{12}}}$

Hope it helps :)

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A factory robot recently examined some bulbs, of which 2 were flawed and 36 were not. Considering this data, how many flawed bul

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Answer: 1 bulb

Step-by-step explanation:

Using the proportion of flawed bulbs in the first scenario, you can get the number of flawed bulbs in the other bath.

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2 years ago

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3 years ago

How do you integrate arctan(x dx? i think that if you simplify the integral you get:?

Temka [501]

Integration by parts will help here. Letting $u=\arctan x$ and $\mathrm dv=\mathrm dx$ , you end up with $\mathrm du=\dfrac{\mathrm dx}{1+x^2}$ and $v=x$ . Now

$\displaystyle\int\arctan x\,\mathrm dx=uv-\int v\,\mathrm du$
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For the remaining integral, setting $y=1+x^2$ gives $\dfrac{\mathrm dy}2=x\,\mathrm dx$ , so

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Putting everything together, you end up with

$\displaystyle\int\arctan x\,\mathrm dx=x\arctan x-\frac12\ln(1+x^2)+C$