Answer:
Step-by-step explanation: A multiple is many, so if you were assigned to a
group project you would have multiple people in your group like more than 5 , 7 etc.
Or in math term if you're dividing a number by another number without a remainder
Answer:
35,829,630 melodies
Step-by-step explanation:
There are 12 half-steps in an octave and therefore
arrangements of 7 notes if there were no stipulations.
Using complimentary counting, subtract the inadmissible arrangements from
to get the number of admissible arrangements.

can be any note, giving us 12 options. Whatever note we choose,
must match it, yielding
. For the remaining two white key notes,
and
, we have 11 options for each (they can be anything but the note we chose for the black keys).
There are three possible arrangements of white key groups and black key groups that are inadmissible:

White key notes can be different, so a distinct arrangement of them will be considered a distinct melody. With 11 notes to choose from per white key, the number of ways to inadmissibly arrange the white keys is
.
Therefore, the number of admissible arrangements is:

Cosine law
a²=b²+c²-2ab*cosA
a²=13²+11²-2*13*11*cos(108)≈378.37
a≈19.45
When you talk about the speed of a car, you usually say something in miles per hour. For example, you say, 'I drove 40 miles per hour.' Normally, you don't say, 'I drove 120 miles per 3 hours.' Figure out how to convert<span> a </span>rate<span> like 120 miles per 3 hours to the</span>unit rate<span> of 40 miles per hour by watching this tutorial.</span>