All categories

3 years ago

What is -(2×7)+(4g×9a)

Mathematics

1 answer:

kotykmax [81]3 years ago

4 0

I think its 162 but i dont know so hope this helps sorry if it dont

You might be interested in

Given that f(x)=-3x+9, what is f(4)?

timurjin [86]

Answer:

F(4) = -3

Step-by-step explanation:

First, you would plug in 4 for x. PEMDAS, so you would multiply -3 and 4, giving you -12. Then add 9, which gives you -3.

6 0

3 years ago

Read 2 more answers

What is (-12x+6)+(4x-12)

mafiozo [28]

Final Result :

-2 • (4x + 3)

Processing ends successfully

6 0

3 years ago

Read 2 more answers

The value of y is directly proportional to the value of x. When x=3.5, the value of y is 14. What is the value of y when x = 28?

inna [77]

Answer:

x = 7

Step-by-step explanation:

y = 14

14 x 2 = 28

Therefore:

3.5 x 2 = 7

7 0

2 years ago

What is the modulus of |9+40i|?

Talja [164]

Answer:

Step-by-step explanation:

We know that complex numbers are a combination of real and imaginary numbers

Real part is x and imaginary part y is multiplied by i, square root of -1

Modulus of x+iy = $\sqrt{x^2+y^2}$

Here instead of x and y are given 9 and 40

i.e. 9+40i

Hence to find modulus we square the coefficients add them and then find square root

|9+49i| = $\sqrt{9^2+40^2} =\sqrt{1681}$

By long division method we find that

|9+40i| =41

6 0

3 years ago

Read 2 more answers

Rationalize the denominator of $\frac{5}{2+\sqrt{6}}$. The answer can be written as $\frac{A\sqrt{B}+C}{D}$, where $A$, $B$, $C$

horrorfan [7]

Answer:

$A +B+C+D = 3$ is the correct answer.

Step-by-step explanation:

Given:

$\frac{5}{2+\sqrt{6}}$

To find:

$A+B+C+D = ?$ if given term is written as following:

$\frac{A\sqrt{B}+C}{D}$

<u>Solution:</u>

We can see that the resulting expression does not contain anything under $\sqrt$ (square root) so we need to rationalize the denominator to remove the square root from denominator.

The rule to rationalize is:

Any term having square root term in the denominator, multiply and divide with the expression by changing the sign of square root term of the denominator.

Applying this rule to rationalize the given expression:

$\dfrac{5}{2+\sqrt{6}} \times \dfrac{2-\sqrt6}{2-\sqrt6}\\\Rightarrow \dfrac{5 \times (2-\sqrt6)}{(2+\sqrt{6}) \times (2-\sqrt6)} \\\Rightarrow \dfrac{10-5\sqrt6}{2^2-(\sqrt6)^2}\ \ \ \ \ (\because \bold{(a+b)(a-b)=a^2-b^2})\\\Rightarrow \dfrac{10-5\sqrt6}{4-6}\\\Rightarrow \dfrac{10-5\sqrt6}{-2}\\\Rightarrow \dfrac{-5\sqrt6+10}{-2}\\\Rightarrow \dfrac{5\sqrt6-10}{2}$

Comparing the above expression with:

$\frac{A\sqrt{B}+C}{D}$

A = 5, B = 6 (Not divisible by square of any prime)

C = -10

D = 2 (positive)

GCD of A, C and D is 1.

So, $A +B+C+D = 5+6-10+2 = \bold3$

5 0

3 years ago