1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Iteru [2.4K]
3 years ago
9

Change to a whole or mixed 17/5

Mathematics
2 answers:
krek1111 [17]3 years ago
5 0

Answer:

3  2/5

Step-by-step explanation:

17/5

How many times does 5 go into 15

5*3 =15   3 times

17-15 =2  so there is 2 left over.  This goes over the denominator

3  2/5

Daniel [21]3 years ago
4 0

Answer:

<h2>3 2/5</h2>

Step-by-step explanation:

17/5 =  17 \div  5 = 3\:remainder\: 2\\\\= 3\frac{2}{5}

You might be interested in
In a certain region each person is understood to live either in the city or the suburbs. Each year 6% of the city population mov
Kaylis [27]

Answer:

y₁=x₁+0.04x₂

y₂=x₂+0.06x₁

Step-by-step explanation:

In the first year, number of people who live:

In the city= x₁

In the suburb=x₂

New Population in the next year

In the city= y₁

In the suburb=y₂

If each year 6% of the city population moves to the suburb,

New Suburb Population=Previous Population+Immigrants

y₂=x₂+0.06x₁

If each year 4% of the suburb population moves to the city,

New City Population=Previous Population+Immigrants

y₁=x₁+0.04x₂

y₁=x₁+0.04x₂

y₂=x₂+0.06x₁

5 0
3 years ago
A coin is tossed 88 times. what is the probability of getting all tails? express your answer as a simplified fraction or a decim
dmitriy555 [2]

|\Omega|=2^{88}=309485009821345068724781056\\ |A|=1\\\\ P(A)=\dfrac{1}{309485009821345068724781056}

4 0
2 years ago
Quadratic Equation
Natasha_Volkova [10]

Step-by-step explanation:

The sum of ages of two friends is 13 years.

The product of their ages is 42.

<em>Let the age of 1st friend and 2nd friend is x, y respectively.</em>

<em>1 st condition= The sum of ages of two friends is 13 y</em><em>r</em><em>s. </em>

i.e x+y = 13........ (I)

<em>2nd condition= The product of their ages is 42.</em>

i.e X*y = 42........(ii)

From equation (I)

X+y = 13

or, X = 13-y........ (iii)

<em>Putting the equation (iii) in equation (ii).</em>

X*y= 42

(13-y) * y = 42

13y - y^2 = 42

{y}^{2}  - 13y + 42 = 0

{y}^{2}   - (7 + 6)y + 42= 0

{y}^{2}  - 7y - 6y + 42 = 0

y(y - 7) - 6(y - 7) = 0

(y - 6) (y - 7) = 0

Either; y-6 = 0

y = 6

Or;

y-7=0

y = 7

<em>Keeping the value of y as "7" in equation (ii)</em>

x*y = 42

7x = 42

X = 42/7

Therefore, the value of X is 6.

Therefore, either 1st friend is 6 years and 2nd is 7 years.

<em><u>H</u></em><em><u>o</u></em><em><u>p</u></em><em><u>e</u></em><em><u> </u></em><em><u>it </u></em><em><u>helps</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>

7 0
3 years ago
Can you help asap pls
jeka94

2 + 2 = 4  5 + 5 = 10 + 4 = 14 your answer is 14

Step-by-step explanation:

4 0
2 years ago
3) Caleb's cellphone says that it is 20% charged. He has 45
ra1l [238]

Answer:

225 minutes

Step-by-step explanation:

45 min = 20% = 20/100

20 x 5 = 100

45 x 5 = 225

3 0
3 years ago
Other questions:
  • Factor completely 3x^3+6x^2-24x
    15·1 answer
  • <img src="https://tex.z-dn.net/?f=7xy%28x%20-%207%29%20%3D%20%20" id="TexFormula1" title="7xy(x - 7) = " alt="7xy(x - 7) = " a
    11·1 answer
  • Is 2 a prime number?
    7·2 answers
  • Find the value or values of c that satisfy the equation f(b) - f(a) b - a
    5·1 answer
  • Who can help me on this it’s due soon!
    7·1 answer
  • There are 27 questions on an algebra test. All of the questions are multiple choice or constructed response. The number of const
    6·1 answer
  • Benifits of social media when reporting about gbv
    9·1 answer
  • Write an equation for a line thst is perpendicular to the line given by x=5 and passes through 1,0
    7·1 answer
  • Convert the angle O= 35° to radians.<br> Express your answer exactly.<br> radians
    10·1 answer
  • This is really hard pls Help whats 9+10<br> ​
    14·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!